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kvasek [131]
3 years ago
5

An account with $600 earns 4% simple interest per year. The next year all the money is put into a new account that earns 4.5% si

mple interest per year. How much money does the account have at the end of the second year? Explain.
Mathematics
2 answers:
N76 [4]3 years ago
7 0
[First Year]
$600 • 0.04 • 1 year
600 • 0.04 = 24 • 1 = 24

[Second Year]
$600 • 0.045 • 1 year
600 • 0.045 = 27 • 1 = 27

24 + 27 = $51

I believe this is correct and I hope this helps! :)
guapka [62]3 years ago
3 0

Answer:

The account will have $51 at the end of the second year.

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FOR 15 POINTS Determine whether each given value of h makes the inequality 4h + 13 ≤ −7 true. Select Yes or No for each value.
Norma-Jean [14]

Answer:

Yes, no, yes

Step-by-step explanation:

7 0
3 years ago
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At dinner, the meal cost $22 and a $1.87 sales tax was added to the bill. What would be the total amount if the meal cost $80.
Helen [10]
1.87 is 8.5% of 22 so 8.5% of 80 is 0.085 x 80 so $6.80
3 0
2 years ago
A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d
UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

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5 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
2 years ago
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qwelly [4]
Answer is (a)
its a binomial
not a monomial
7 0
3 years ago
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