<em>A player has made 188 free throw attempts, and in that time has made a total of 129 free throws. FT % = 0.686 Therefore, this player has an FT% of .686, or 68.6%. Wikipedia – Free throw percentage season leaders and Free Throw (Basketball) – Wikipedia entries on the concept of free throws.</em>
Answer: y= 3/2x+1
Step-by-step explanation:
Hence, the percentage increment is 33.25%
Multiply 10.5 and 23.5 to get 246.75. Divide that by 3 and you have your answer, 82.25.
