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olganol [36]
2 years ago
13

Name a pair of adjacent angles

Mathematics
1 answer:
likoan [24]2 years ago
8 0

Answer:

Angle 1 and Angle 2 are adjacent angles.

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A circular mat has a circumference of 220 centimeters. Find the radius rounded to the nearest whole number.
Papessa [141]
С = 2πr  [π≈3.14]

220 = 2 * 3.14 * r
220 = 6.28r 
r = 220/6.28 ≈ 35 cm  ←  <span>to the nearest whole number.</span>
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3 years ago
Find the missing length indicated.<br> х<br> 12<br> 9<br> X =<br> units
madam [21]

Answer:

16

Step-by-step explanation:

9/12=12/x

x=16

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What is the prime factorization of 58
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The prime factorisation for 58 is 2 x 29

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Add Four on both sides
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What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
2 years ago
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