Let n be the number 18=60% of n
18=0.6n
18/0.6=n
30=n
The square box is enough to fit the pizza with a diameter of 10 inches inside. Since the area of the square box is more than the area of the pizza, the pizza fits easily in the square box.
<h3>What is the area of the circle and the square?</h3>
The area of the circle is
Ac = πr² = πd²/4 sq. units
Where r is the radius and d is the diameter of the circle.
The area of the square is given by
As = s² sq. units
Where s is the length of the side of a square.
<h3>Calculation:</h3>
It is given that a pizza(in a circular shape) with a diameter d = 10 in is to be placed in a square box of the same length as the diameter of the pizza.
So,
The area of pizza is
Ap = Ac = πd²/4 sq. units
= π(10)²/4
= 25π
= 78.54 sq. in
Then, the area of the square box with the length same as the diameter of the pizza is,
As = d²
= 10²
= 100 sq. in
Since the area of the square is more than the area of the pizza (100 sq. inch > 78.54 sq. inch), the pizza easily fits into the square box.
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F(x) = x^2 + 1
f(4) = 4^2 + 1 = 16 + 1 = 17
2*f(4) = 2 * 16 = 32
Answer: 11.25 secs
Step-by-step explanation:
So in this sense the rockets origin or the ground is modeled at h=0 so the time required if used on a table shows that h=0 between the values of 11 and 12. So if you plug and chug decimal values between these two values you get exactly 0 at t=11.25 so it takes approximately 11.25 seconds for the rocket to return to the ground
By this equation y = 1,716 - 112x he find that how much money he still owes after each month of the plan.
According to the statement
Jonathan bought a new computer for $1,716
He will pay $143 a month for 12 months.
Total amount he will for 12 months is 143(`12)
Now,
y = the money he still owes
x = the number of months (from x = 0 to x = 12)
y = 1,716 - 112x
So, By this equation y = 1,716 - 112x he find that how much money he still owes after each month of the plan.
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