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3 years ago

In the triangle below, solve for x

Mathematics

1 answer:

Andrej [43]3 years ago

4 0

Answer:

105°

Step-by-step explanation:

Sum of all sides of a triangle = 180°

x = 180° - (45° + 30°)

= 180° - 75°

= 105°

Therefore x is 105°. Hope you understood :)

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PLEASE DIE TODAY I NEED MY GRADE UP it is not 12.5 this is my last attempt I think 15 points

Volgvan

Answer:

25%

Step-by-step explanation:

1/2 ×1/2

=1/4

=0.25

which is 25%

7 0

3 years ago

The number 'N' of cars produced at a certain factory in 1 day after 't' hours of operation is given by N(t)=100t-5t^2, 0< or

Luden [163]

Given: C(N) = 15,000 + 8000N 

In the above equation simply substitute:
N(t) = 100t - 5t^2
for N

Therefore:
C(t) = 15,000 + 8000{ 100t-5t^2 }
C(t) =15,000 + 800,000t - 40,000t^2.

at t = 5

C(5) = 15,000 + 800,000*5 - 40,000*(5)^2

C(5) = 3,015,000

7 0

3 years ago

Read 2 more answers

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

The value of y varies directly with x, and when x = y = 25. What is the value of

kipiarov [429]

Answer:

A 233.3 or 233 1/3

Step-by-step explanation:

X =1/4

Y =25

1/4 X 100= 25

2 1/3 X 100= 233.3

6 0

2 years ago

Rob is two times as old as Jake. Three years ago the sum of their ages was 21 years. Find their present ages?

spin [16.1K]

Rob is 18
Jake is 9

21-15=6
6+3=9
9x2=18
(No clue how I got 15 )

8 0

3 years ago

Read 2 more answers

In the triangle below, solve for x ​

In the triangle below, solve for x