Question

Find the coordinates of the image of the point A(3, 9) for a dilation with the scale factor of 2/3

Answer 1

The coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be: A'(2, 6)

Step-by-step explanation:

Given the point A with the vertices (3, 9) i.e. A(3,9)

As we know that If the scale factor is between 0 and 1, the image gets shrunk.

In order to dilation with a scale factor of 2/3, just multiply the x and y coordinates of the original point (3, 9) by 2/3.

i.e.

(x, y) → (2/3 x, 2/3 y)

so, the coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be:

A (x, y) → (2/3 x, 2/3 y) = A (2/3 (3), 2/3 (9)) = A'(2, 6)

Therefore, the coordinates of the image of point A(3,9) for dilation with the scale factor of 2/3 will be: A'(2, 6)

( I got it from someone else )

Answer 2

Answer:

A'(2, 6 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then multiply each of the coordinates by $\frac{2}{3}$

A(3, 9 ) → A'( $\frac{2}{3}$ (3), $\frac{2}{3}$ (9) ) → A'(2, 6 )