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Slav-nsk [51]
3 years ago
10

Need help ASAP??? Pick the best answers

Computers and Technology
1 answer:
zloy xaker [14]3 years ago
7 0

Answer:

A and C are correct pick both

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Students with "Red" hair had the highest average number of free throws made on the "Hair Color Summary" table and students with
erik [133]
Babe he is is dis d did d did. D
4 0
3 years ago
You are finally at the stage of the software life cycle where you begin programming. What is this stage called?
nataly862011 [7]
You are finally at the stage of the software life cycle where you begin programming. What is this stage called?

development

5 0
2 years ago
Does anyone know the code for the beaded bracelet on codehs? pls i really need help
kvv77 [185]

Answer:

Explanation:

If it has not changed since the last time that i used codehs then the code should be the following

penup()

forward(-100)

right(90)

pendown()

def beaded_bracelet():

circle(10)

penup()

forward(20)

left(10)

pendown()

for i in range(36):

beaded_bracelet()

Which should complete the entire function as intended.

6 0
3 years ago
For a class Foo, one difference between a variable declared Foo * and a variable declared Foo & is that only the variable de
Studentka2010 [4]

Answer:

False.

Explanation:

When we declare a variable as reference type we have to initialize that variable otherwise the compiler will give error that the reference variable is not initialized.You also cannot initialize the variable Foo& with NULL value because it is a reference variable and we have to initialize it.

On the other there is no need to initialize the variable Foo * since it is a pointer it can also store NULL value.

So the answer is only Foo* can store NULL value not Foo &.

5 0
3 years ago
The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided
poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

 

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

       System.out.println();

       people += 5;

   }

}

}

4 0
3 years ago
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