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s2008m [1.1K]
3 years ago
12

Hurry Need Help I Will Give Brainliest!!

Mathematics
2 answers:
Bingel [31]3 years ago
5 0

Congruent is the answer

max2010maxim [7]3 years ago
4 0

Answer:

opposite, gib me brainliest plss.

Step-by-step explanation:

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What is the measure of the missing angle in the triangle below?
DedPeter [7]
Answer: 41

Step-by-step explanation: all triangles equal 180° so you add the 2 angles you know, 52+87=139. Then you take the 180 and subtract the 139 to get 41°
5 0
3 years ago
Read 2 more answers
Y=3x-5 y=6x-8 show all steps and write the solution
m_a_m_a [10]

Step 1: Set the two equations equal to each other and solve for x.

3x -5 = 6x - 8

3x + (-5+5) = 6x -8 + 5

(3x - 6x) = (6x - 6x) - 3

-3x/-3  = -3/-3

x = 1

Step 2: To solve for y take one of the given equation of your choice (for the purpose of this explanation I will only do y = 3x - 5) and replace x with 1, then solve for y

y = 3(1) - 5

y = 3 - 5

y = -2

(1,-2)

Check:

-2 = 3(1) - 5 ---> - 2 = -2

-2 = 6(1) - 8 ---> -2 = -2

Hope this helped!

5 0
2 years ago
Read 2 more answers
Hi everybody!
Irina-Kira [14]
That answer is  A and B pick one
5 0
2 years ago
Jason tracked the days of the week for the last 50 times he was assigned homework.
vovangra [49]

Answer:

Hello, mizuki here to help!

The correct answer would be C

Step-by-step explanation:

Ok, so the total of homework he got was 50, and the number of homework he got in monday was 16.

So.... it should be expressed as 16/50 which would be 0.32

3 0
3 years ago
If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v
pochemuha

Answer:

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = 5000(1 - \frac{1}{40}t )^2  , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = 2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )

V'(t) = 2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )

When we simplify the above, we get

V'(t) = -250(1 - \frac{1}{40}t)

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0
3 years ago
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