At 400K both compounds are gases. At this temperature, which compound, CH4(g) or CCl4(g) , behaves more like an ideal gas
1 answer:
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5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.
Explanation:
The balanced equation:
2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)
data given:
volume of AgNO3 = 0.2 L
molarity of AgNO3 = 0.200 M
atomic weight of AgCl= 143.32 gram/mole
from the formula, number of moles can be calculated
Molarity =
number of moles of AgNO3 = 0.04
From the reaction:
2 moles of AgNO3 reacts to form 2 moles of AgCl
0.04 moles of AgNO3 reacts to form x mole of AgCl
=
= 0.04 moles of AgCl is formed
mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl
mass of AgCl = 0.04 x 143.32
= 5.732 grams of AgCl is formed.
Explanation:
Volume of intravenous solution to be delivered = 50 mL
1) Rate of drops per milliliter of the solution = r = 60 drops/mL
Number of drops delivered :
Time required to deliver 3000 drops = t
Rate of drop solution with respect to time = R = 1 drop/second
t = 3000 seconds = 50 minutes (1 min = 60 seconds)
Number of drops delivered 3000.
50 minutes are required to deliver 50 mL of intravenous solutions.
2) Rate of drops per milliliter of the solution = r = 15 drops/mL
Number of drops delivered :
Time required to deliver 750 drops = t
Rate of drop solution with respect to time = R = 1 drop/second
t = 750 seconds = 12.5 minutes (1 min = 60 seconds)
Number of drops delivered 750 .
12.5 minutes are required to deliver 50 mL of intravenous solutions.