The mass and volume has direct proportional to each other.
<h3>What is the relationship between mass and volume?</h3>
The volume of the object is directly proportional to its mass which means that if the volume increases the mass of the object increases also increase and vice versa. Due to this direct relationship, the line of regression will go straight between X and Y axis.
So we can conclude that mass and volume has direct proportional to each other.
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Answer: C diamond has a different crystal structure from graphite
Explanation:
Answer:
Measuring distances to stars through stellar parallax. Measuring distances to stars through the moving cluster method. Astronomers measure the temperature of a star by looking at the star's color and its spectrum. The apparent brightness of a star tells how bright it seems to us
Explanation:
Answer:
E
Explanation:
None of the above
The atom with the symbol S is called sulphur Sulphur has atomic number 16 which means that it has 16 protons. Sulphur-32 has 32 nucleons - 16 protons and 16 neutrons.Sulfur is a chemical element It is nonmetallic. Under normal conditions, sulfur atoms form cyclic octatomic molecules with a chemical formula S8. Elemental sulfur is a bright yellow, crystalline solid at room temperature.
<u>36 ml of NaOh and</u><u> 464 ml</u><u> of </u><u>HCOOH</u><u> would be enough to form 500 ml of a buffer with the same pH as the buffer made with </u><u>benzoic acid </u><u>and NaOH.</u>
What is benzoic acid found in?
- Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
- Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.
Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.
Amount of moles of NaOH -2 × 0.025 = 0.05 mol
Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol
In this case, we can calculate the pH produced by the buffer of these two reagents, as follows
![pH = pKa + log\frac{base}{acid}](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%5Cfrac%7Bbase%7D%7Bacid%7D)
![4.2 + log\frac{0.05}{0.045} = 4.245](https://tex.z-dn.net/?f=4.2%20%2B%20log%5Cfrac%7B0.05%7D%7B0.045%7D%20%3D%204.245)
We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows
![pH = pKa + log\frac{base}{acid}](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%5Cfrac%7Bbase%7D%7Bacid%7D)
![4.245 = 3.75 + log\frac{base}{acid}](https://tex.z-dn.net/?f=4.245%20%3D%203.75%20%2B%20log%5Cfrac%7Bbase%7D%7Bacid%7D)
![log\frac{base}{acid} = 0.5](https://tex.z-dn.net/?f=log%5Cfrac%7Bbase%7D%7Bacid%7D%20%3D%200.5)
![\frac{base}{acid} = 3.162](https://tex.z-dn.net/?f=%5Cfrac%7Bbase%7D%7Bacid%7D%20%3D%203.162)
Now we must solve the equation above. This will be done using the following values
![\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L](https://tex.z-dn.net/?f=%5Cfrac%7B2%280.5%20-%20x%29%7D%7B0.2x%20-%202%280.5%20-%20x%29%7D%20%3D%200.464%20L)
With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.
NaOH volume
( 0.5 - 0.464)L
0.036L .................... 36ml
HCOOH volume
500 - 36 = 464mL
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