All categories

3 years ago

What is the molarity of a solution which contains 0.88 g of barium chloride in 120.0 mL of solution

Chemistry

1 answer:

Andre45 [30]3 years ago

6 0

Answer:00.73

Explanation:

Divide 0.88g by 120.0ml

You might be interested in

What does Gibbs free energy depend on? O A. It depends on the rate and quantity of the reaction. O B. It depends on the activati

Oksana_A [137]

Answer:

C: It depends on the entropy and enthalpy of the reaction.

Explanation:

Gibbs free energy is defined as the maximum amount of non-expansion work that can be gotten from a closed system. Now this work is usually done in place of the system’s internal energy and Energy that is not extracted as work is usually exchanged with the immediate surroundings in the form of heat.

5 0

3 years ago

The rate constant for the second-order reaction: 2NOBr(g) → 2NO(g) + Br2(g) is 0.80/(M · s) at 10°C. Starting with a concentrati

a_sh-v [17]

Answer : The concentration of NOBr after 95 s is, 0.013 M

Explanation :

The integrated rate law equation for second order reaction follows:

$k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)$

where,

k = rate constant = $0.80M^{-1}s^{-1}$

t = time taken = 95 s

[A] = concentration of substance after time 't' = ?

$[A]_o$ = Initial concentration = 0.86 M

Now put all the given values in above equation, we get:

$0.80=\frac{1}{95}\left (\frac{1}{[A]}-\frac{1}{(0.86)}\right)$

[A] = 0.013 M

Hence, the concentration of NOBr after 95 s is, 0.013 M

4 0

3 years ago

igor_vitrenko [27]

The answer is

e o i and a

not really sure forgive me if im wrong

7 0

3 years ago

100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the

grandymaker [24]

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

3 0

3 years ago

How much silver chloride is precipitated when 25.0 g of calcium chloride and 25.0 g of silver nitrate are mixed together in a be

Burka [1]

Answer:

21.09 g of AgCl

Explanation:

Hopefully the picture is clear and the method is understandable.

For more information go to

https://socratic.org/questions/5631d10b11ef6b4609a78ee2

7 0

3 years ago