Answer:
CaCO3 (s) → CaO (s) + CO2 (g)
The mass of carbonate that must have reacted was 43.03 grams
Explanation:
CaCO3 → CaO + CO2
Relation between reactant and product is 1:1
Let's apply the Ideal Gas Law to find out the moles of CO2 which were produced.
P . V = n . R . T
1 atm . 23 L = n . 0.082 L.atm/mol.K . 653K
(1atm . 23L) / (0.082 mol.K/L.atm . 653K) = n
0.43 moles = n
0.43 moles of CO2, were produced from 0.43 moles of CaCO3.
Molar weight of CaCO3 = 100.08 g/m
Mass = Molar weight . moles
Mass = 100.08 g/m 0.43 m = 43.03 g
The curved movement of air or water is the result of which of these:
The answer is B
Answer:
0.4429 m
Explanation:
Given that mass % of the ethanol in water = 2%
This means that 2 g of ethanol present in 100 g of ethanol solution.
Molality is defined as the moles of the solute present in 1 kilogram of the solvent.
Given that:
Mass of 
= 2 g
Molar mass of = 46.07 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass of water = 100 - 2 g = 98 g = 0.098 kg ( 1 g = 0.001 kg )
So, molality is:
<u>Molality = 0.4429 m</u>
It is hard to answer this because not much information is given.
Answer:
2,5
Explanation:
When move from left to right in periodic table atomic number increases. So element to the right of carbon has one electron more than carbon therefore it's electronic configuration would be 2,5
