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Orlov [11]
3 years ago
8

16g 2g/cm3 what is the Volume

Physics
1 answer:
lord [1]3 years ago
7 0

Answer:

V =  1.25E-7 cubic meter

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A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s
saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

F= \frac{mv^2}2

La energía gravitacional por,

F=\frac{GM_cm}{d}

Where m is the mass, v is the velocity, G the gravitational constant M_e the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

E= \frac{mv^2}2+\frac{GM_em}{d}

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2

The case of the comet is a closed orbit, so,

E<0

\frac{mv^2}2+\frac{GM_em}{d}

For parabolic orbit

E=0

\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2

For the sun and the earth

\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}

v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r

where R \approx 1AU

q^2d  For elliptical orbit

8 0
3 years ago
ASAP pls answer right I will mark brainiest . All I know is 4. Is A
Sonja [21]

Answer:

Q1: B.2 Q2: B.Waxing crescent Q3: A.Waxing Gibbous

Explanation:

4 0
3 years ago
California has been spending money to establish desalination plants. The state is preparing for
Stella [2.4K]
Extracting saltine from the water.
4 0
3 years ago
Emilio tries to jump to a nearby dock from a canoe that is floating in the water.Instead of landing on the dock, he falls into t
kow [346]
The reaction of him pushing off a floating object pushes it away causing him to lose power and balance
7 0
3 years ago
A 34.0 %-efficient electric power plant produces 800 MW of electric power and discharges waste heat into 20∘C ocean water. Suppo
mojhsa [17]

Answer:

77647

Explanation:

\eta = Efficiency = 34%

Power used in 1 home = 0.02 MW

Total power is

P=\dfrac{800}{\eta}\\\Rightarrow P=\dfrac{800}{0.34}\\\Rightarrow P=2352.94117\ MW

Waste of power

2352.94117-800=1552.94117\ W

Number of homes would be given by

n=\dfrac{1552.94117}{0.02}=77647.0585\ homes

The number of homes that could be heated with the waste heat of this one power plant is 77647

8 0
3 years ago
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