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Digiron [165]
2 years ago
12

Can someone help me solve this?

Mathematics
1 answer:
stiv31 [10]2 years ago
5 0

Answer:

\sqrt{x} -\frac{16}{\sqrt{x} }

Step-by-step explanation:

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What is the x-coordinate of the solution to the system?<br> { 2x-3y= -27<br> -3x+2y= 23
UkoKoshka [18]

Answer:

x = 41 and y = 76

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
The strength of a cable is proportional to the square of its diameter. If a 2-cm cable will support 800kg, how much will a 3-cm
xz_007 [3.2K]
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
3 0
3 years ago
I need help on thi and the first person who answer correctly gets a BRANLIST​ and show work​
const2013 [10]

Answer:

w<6 THE SMALL LINE UNDER THE LESS THAN SIGN IS STILL THERE I JUST CANNOT ADD IT

Step-by-step explanation:

first solve the equation to the right.

-3(2w+1) = -6w-3

now solve the whole equation

-33-w< -6w-3

-w+6w < -3+33

5w < 30

divide the 5 from both sides to simplify

5/5w < 30/5

w < 6

THE ANSWER IS w < 6

3 0
2 years ago
Can someone please help me with these math problems ASAP?!<br> Thanks in advance! ;)
Mamont248 [21]

Answer:

11) Here given Function,

f(x) = \sqrt{2x-11}

And, g(x) = -|0.1|x+5

For f(x) = g(x)

\sqrt{2x-11}=-|0.1|x+5

2x-11=(-|0.1|x+5)^2

2x-11=0.01x^2 - 10|0.1|x+25

2x=0.01x^2 - 10|0.1|x+25+11

2x=0.01x^2 - 10|0.1|x+36

0.01x^2 - 10|0.1|x - 2x+36=0

When we solve this equation,

We found,

 x = 12.5227 ≈ 12.53

Thus, the required solution is, x = 12.53

12) Here the height of rocket A in x second,

f(x) = -16x^2+74x+9

And, The height gain by the rocket B in x seconds,

g(x) = -16x^2+82x

If at x seconds both A and B gain the same height,

That is, f(x) = g(x)

⇒ -16x^2+74x+9= -16x^2+82x

⇒74x + 9 = 82x

⇒ 82x - 74x = 9

⇒ 8x = 9

⇒ x = 1.125 ≈ 1.13

Thus, the required solution is x = 1.13 seconds (approx)


4 0
3 years ago
How do you graph an explict equation
morpeh [17]
I think this might help but sorry if it does not but I hope it does :) :D - https://learnzillion.com/lesson_plans/5701-writing-an-explicit-formula-for-the-graph-of-an-exponential-relationship/
5 0
3 years ago
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