The abscissa of the ordered pair, that is the x-coordinate, is equal to 1 and the ordinate, the y-coordinate, is equal to -1. In the cartesian plane, this point lies in the fourth (IV) quadrant. The standard position of the angle is that which has one of its side is in the x-axis.
Solve for the hypotenuse of the right triangle formed.
h = sqrt((-1)² + (1)²) = √2
Below items show the calculation for each of the trigonometric functions.
sin θ = opposite/hypotenuse = y/h = (-1)/(√2) = -√2/2
cos θ = adjacent/hypotenuse = x/h = (1)/√2 = √2/2
tan θ = opposite/adjacent = y/x = -1/1 = -1
Answer:
I think D
Step-by-step explanation:
remember that local minimuns are points in which the function was decreasing and starts increasing.
you can try two ways of doing it, graphing the functions or using derivatives.
since this are twelve functios the easier way is to graph them.
start by function y=x
in this case this function is continously increasing as x increases, which means that it does not have any local maxima or minima.
now do the same for

this graph has a local minima on th