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ICE Princess25 [194]
3 years ago
7

To determine if carrot juice helps improve heart conditions, a juicing company asks a random sample of 100 adults about whether

or not they drink carrot juice and their heart condition. The company finds an association between drinking carrot juice and healthy heart conditions.
Which statement is true about a possible confounding variable?

A possible confounding variable is the amount of exercise. Those that drink carrot juice may be more concerned about their health and exercise more, which explains the healthy heart conditions.

A possible confounding variable is eating dinner at a fast-food restaurant. Those that eat at fast-food restaurants are more likely to not drink carrot juice and the fast food would explain the healthy heart conditions.

A possible confounding variable is the amount of exercise. Those that drink carrot juice are not concerned about their health and are more likely to not exercise, which does not improve heart conditions.

A possible confounding variable is eating fast food. Those that drink carrot juice are more concerned about their health and are more likely to not eat fast food which does not improve heart conditions.
Mathematics
2 answers:
sergeinik [125]3 years ago
8 0

Answer: A is the correct answer

Step-by-step explanation:

I just did the assignment

Bad White [126]3 years ago
4 0

Answer:

the answer would be A

Step-by-step explanation:

i am in tenth grade and i have no clue what i am doing. but some how i figured it out so read between the lines thats all the advice i have have a great day.

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Return to the credit card scenario of Exercise 12 (Section 2.2), and let C be the event that the selected student has an America
Nadya [2.5K]

Answer:

A. P = 0.73

B. P(A∩B∩C') = 0.22

C. P(B/A) = 0.5

   P(A/B) = 0.75

D. P(A∩B/C) = 0.4

E. P(A∪B/C) = 0.85

Step-by-step explanation:

Let's call A the event that a student has a Visa card, B the event that a student has a MasterCard and C the event that a student has a American Express card. Additionally, let's call A' the event that a student hasn't a Visa card, B' the event that a student hasn't a MasterCard and C the event that a student hasn't a American Express card.

Then, with the given probabilities we can find the following probabilities:

P(A∩B∩C') = P(A∩B) - P(A∩B∩C) = 0.3 - 0.08 = 0.22

Where P(A∩B∩C') is the probability that a student has a Visa card and a Master Card but doesn't have a American Express, P(A∩B) is the probability that a student has a has a Visa card and a MasterCard and P(A∩B∩C) is the probability that a student has a Visa card, a MasterCard and a American Express card. At the same way, we can find:

P(A∩C∩B') = P(A∩C) - P(A∩B∩C) = 0.15 - 0.08 = 0.07

P(B∩C∩A') = P(B∩C) - P(A∩B∩C) = 0.1 - 0.08 = 0.02

P(A∩B'∩C') = P(A) - P(A∩B∩C') - P(A∩C∩B') - P(A∩B∩C)

                   = 0.6 - 0.22 - 0.07 - 0.08 = 0.23

P(B∩A'∩C') = P(B) - P(A∩B∩C') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.4 - 0.22 - 0.02 - 0.08 = 0.08

P(C∩A'∩A') = P(C) - P(A∩C∩B') - P(B∩C∩A') - P(A∩B∩C)

                   = 0.2 - 0.07 - 0.02 - 0.08 = 0.03

A. the probability that the selected student has at least one of the three types of cards is calculated as:

P = P(A∩B∩C) + P(A∩B∩C') + P(A∩C∩B') + P(B∩C∩A') + P(A∩B'∩C') +              

     P(B∩A'∩C') + P(C∩A'∩A')

P = 0.08 + 0.22 + 0.07 + 0.02 + 0.23 + 0.08 + 0.03 = 0.73

B. The probability that the selected student has both a Visa card and a MasterCard but not an American Express card can be written as P(A∩B∩C') and it is equal to 0.22

C. P(B/A) is the probability that a student has a MasterCard given that he has a Visa Card. it is calculated as:

P(B/A) = P(A∩B)/P(A)

So, replacing values, we get:

P(B/A) = 0.3/0.6 = 0.5

At the same way, P(A/B) is the probability that a  student has a Visa Card given that he has a MasterCard. it is calculated as:

P(A/B) = P(A∩B)/P(B) = 0.3/0.4 = 0.75

D. If a selected student has an American Express card, the probability that she or he also has both a Visa card and a MasterCard is  written as P(A∩B/C), so it is calculated as:

P(A∩B/C) = P(A∩B∩C)/P(C) = 0.08/0.2 = 0.4

E. If a the selected student has an American Express card, the probability that she or he has at least one of the other two types of cards is written as P(A∪B/C) and it is calculated as:

P(A∪B/C) = P(A∪B∩C)/P(C)

Where P(A∪B∩C) = P(A∩B∩C)+P(B∩C∩A')+P(A∩C∩B')

So, P(A∪B∩C) = 0.08 + 0.07 + 0.02 = 0.17

Finally, P(A∪B/C) is:

P(A∪B/C) = 0.17/0.2 =0.85

4 0
3 years ago
EFGH is translated 3 units to the left and 7 units up.<br> What are the coordinates of H'?
Nikitich [7]
Where was H originally?
8 0
3 years ago
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Total surface area of a cube is 1014cm^2. It's volume will be :
Karolina [17]

Answer:

Option A (2197 cm³)

Step-by-step explanation:

For a cube with length of each side "a" , it's

  • Total Surface Area = 6a²
  • Volume = a³

_____________________________________________

According to the question ,

Total Surface Area = 1014 cm²

Let the length of each side of cube be 'a'.

Using the formula ,

6a^{2} =1014

=> a^{2} =\frac{1014}{6} = 169

=> a = \sqrt{169} = +13 \: or  -13

But length can't be negative . So , length of each side = 13 cm

∴ Volume of cube = 13³ = 2197 cm³

8 0
3 years ago
Find the value of 50 5x + 15<br>​
lukranit [14]
7
5 times 7
equals 35
then you add 15
and get 50
3 0
3 years ago
Find the unit rate<br><br> 8 hits in 22 games
Aleksandr [31]

Answer:

0.363636

Step-by-step explanation:

Hits per game is hits / games

= 8 / 22

= 0.363636363

8 0
3 years ago
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