The answer is 54, 5 is 1 more than 4, they equal 9, 54 is 6 times greater than 9
Answer:
Step-by-step explanation:
We that the area of a circle is Pi times r^2 where r is the radius
Let A be the area of the first circle and S the area of the second one and T the total one
A=4^2× Pi
S=6^2× Pi
T = Pi( 4^2 +6^2)
= Pi ( 16+36) = Pi× 52
52 is the radius square
So r = root square 52 = 2 root square 13
Answer:
(C-D)/A = B
Step-by-step explanation:
C = AB + D
Subtract D from both side
C-D = AB + D-D
C-D = AB
Divide each side by A
(C-D)/A = AB/A
(C-D)/A = B
Answer:
The numbers are
22 and 23 to solve a problem like this, we need to read and define as we go. Let me explain. So we know that there are two consecutive integers. They can be
x and x+1
. Since their consecutive, one has to be 1
number higher (or lower) than the other. Ok, so first we need "seven times the larger"( 7x+1)
Next, we need to "minus three times the smaller" 7(x+1)−3x
Is equal to " 957(x+1)−3x=95
Alright! There's the equation, now we just need to solve for x! First we are going to get everything on one side and distribute the 7=7x+7−3x−95=4x−88
Pull out a
=4(x−22)Now that we have two terms, we can set them both equal to
0 and solve.4≠0
This can never be true, lets move to the next term (x−22)=0x=
22 That's it! So your two consecutive numbers are
22
