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kirill [66]
4 years ago
13

Solve C = AB + D for B.

Mathematics
1 answer:
OLEGan [10]4 years ago
8 0

Answer:

(C-D)/A = B

Step-by-step explanation:

C = AB + D

Subtract D from both side

C-D = AB + D-D

C-D = AB

Divide each side by A

(C-D)/A = AB/A

(C-D)/A = B

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Question #1. factor completely p^4-13p^2+40
dsp73

Answer:

Step-by-step explanation:

#1

(p^2-8) (p^2-5)

#2

(p-2) (4p-1)

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3 years ago
Help Please I’ll Give Brainliest :)
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5 tables

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1 = 24 ÷ 3 = 8

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3 years ago
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Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ​ ,0)(, plus minus, square root o
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Answer:

The equation of ellipse centered at the origin

\frac{x^2}{18} +\frac{y^2}{10} =1

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)  

the focus has x-coordinates so the focus is  lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are c^2=a^2-b^2

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a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}

a^{2} =18

a=\sqrt{18}

The equation of ellipse formula

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

we know that a=\sqrt{18} and b=\sqrt{10}

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u />\frac{x^2}{18} +\frac{y^2}{10} =1<u />

                                   

8 0
3 years ago
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Step-by-step explanation:

We are informed that Two fifth of the students wrote a report. This also means that (2/5 × 100) = 40% = 0.4 wrote a report and 0.6 of the students gave a presentation.

From the decimals gotten, we can see that 0.6 is more than 0.4. Therefore, more students gave a presentation. This implies that Dominic is correct.

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