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2 years ago

7

Describe two ways in which gases are similar to liquids in properties

1 answer:

Nadusha1986 [10]2 years ago

7 0

Answer:

they have weak intermolecular forces

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Leah is trying to determine how music affects the growth of plants. She hypothesizes that classical music will cause a plant to

Pani-rosa [81]

Leah's experiment:
A. Takes careful and regular measurements (she measures the growth every day)
B. Has a specific hypothesis and a controlled experiment (the music is the only changing variable, the growth conditions are identical, and this is what she wants to test in her hypothesis)
C. Experimental data that can be recorded and analyzed (measuring the growth of plant fits this)

So the answer must be D, since there is no mention of past research that scientists have found on this topic.

8 0

3 years ago

Read 2 more answers

A gas container has a volume of 446.9 with a temp of 14c. When the volume is decreased to 238.7l the new temp is what

swat32

Answer:

$\frac{V _{1}}{T _{1}} = \frac{V _{2}}{T _{2} } \\ \frac{446.9}{(14 + 273)} = \frac{238.7}{T _{2} } \\ {T _{2}} = \frac{238.7 \times 287}{446.9} \\ {T _{2}} = 153.3 \: kelvin \\ = 119.7 \degree \: c$

7 0

2 years ago

One of the reactions that occurs in a blast furnace, in which iron ore is converted to cast iron, is Fe2O3 + 3CO → 2Fe + 3CO2 Su

Tpy6a [65]

Answer : The percent purity of $Fe_2O_3$ in the original sample is 87.94 %

Explanation :

The given balanced chemical reaction is:

$Fe_2O3+3CO\rightarrow 2Fe+3CO_2$

First we have to calculate the mass of Fe.

$\text{Moles of }Fe=\frac{\text{Mass of }Fe}{\text{Molar mass of }Fe}$

Molar mass of Fe = 55.8 g/mole

$\text{Moles of }Fe=\frac{1.79\times 10^3kg}{55.8g/mole}=\frac{1.79\times 10^3\times 1000g}{55.8g/mole}=3.15\times 10^4mole$

Now we have to calculate the moles of $Fe_2O_3$

From the balanced chemical reaction we conclude that,

As, 2 moles of Fe produced from 1 mole of $Fe_2O_3$

So, $3.15\times 10^4mole$ of Fe produced from $\frac{3.15\times 10^4}{2}=15750$ mole of $Fe_2O_3$

Now we have to calculate the mass of $Fe_2O_3$

$\text{ Mass of }Fe_2O_3=\text{ Moles of }Fe_2O_3\times \text{ Molar mass of }Fe_2O_3$

Molar mass of $Fe_2O_3$ = 159.69 g/mole

$\text{ Mass of }Fe_2O_3=(15750moles)\times (159.69g/mole)=2.515\times 10^6g=2.515\times 10^3kg$

Now we have to calculate the percent purity of $Fe_2O_3$ in the original sample.

Mass of original sample = $2.86\times 10^3kg$

$\text{Percent purity}=\frac{\text{Mass of }Fe_2O_3}{\text{Mass of sample}}\times 100$

$\text{Percent purity}=\frac{2.515\times 10^3kg}{2.86\times 10^3kg}\times 100=87.94\%$

Therefore, the percent purity of $Fe_2O_3$ in the original sample is 87.94 %

3 0

2 years ago

Help plz i need it my mom is mad at me for not knowing this

ohaa [14]

Lol ok ill help the answer is true and she SHOULDNT be mad at you

5 0

3 years ago

A bicyclist travels the first 800 m of a trip with a speed of 10 m/s, the next 500 m with an

bezimeni [28]

Answer:9.18 m/s

Explanation:

The average speed for the entire trip is found ......total distance/total time. Remember r*t=d, so divide both sides by t and get r = d/t.

So the cyclist went 800+500+1200 m = 2500 m for total distance.

10t =800 leads to t=80 sec

5t=500 leads to t=100 sec

13t = 1200 leads to t = 92.3 sec

total time is 272.3 sec

Average speed for the entire trip is 2500 / 272.3 = 9.18 m/s

7 0

2 years ago