Answer:
600.7 moles
Explanation:
Applying,
PV = nRT................... Equation 1
Where P = Pressure of oxygen, V = Volume of oxygen, n = number of moles, R = molar gas constant, T = Temperature.
make n the subject of the equation
n = PV/RT............... Equation 2
From the question,
Given: P = 190 atm, V = 35 L, T = 135 K
Constant: R = 0.082 atm.dm³/K.mol
Substitute these values into equation 2
n = (190×35)/(135×0.082)
n = 600.7 moles of xygen
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Answer:
Yes
Explanation:
You add more force behind the cart with the higher mass. Assuming that its higher mass causes it to weigh more.
Answer:
D. 0.75 grams
Explanation:
The data given on the iridium 182 are;
The half life of the iridium 182,
= 15 years
The mass of the sample of iridium, N₀ = 3 grams
The amount left, N(t) after two half lives is given as follows;
![N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }](https://tex.z-dn.net/?f=N%28t%29%20%3D%20N_0%20%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E%7B%5Cdfrac%7Bt%7D%7Bt_%7B1%2F2%7D%7D%20%7D)
For two half lives, t = 2 × ![t_{(1/2)}](https://tex.z-dn.net/?f=t_%7B%281%2F2%29%7D)
∴ t = 2 × 15 = 30
![\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2](https://tex.z-dn.net/?f=%5Cdfrac%7Bt%7D%7Bt_%7B%281%2F2%29%7D%7D%20%3D%20%5Cdfrac%7B30%7D%7B15%7D%20%3D%202)
![\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75](https://tex.z-dn.net/?f=%5Ctherefore%20N%28t%29%20%3D%203%20%5Ctimes%5Cleft%20%28%5Cdfrac%7B1%7D%7B2%7D%20%5Cright%20%29%5E2%20%3D%200.75)
∴ The amount left, N(t) = 0.75 grams
Answer: D, splitting water into hydrogen and oxygen is a chemical change.