Answer : The cost of gasoline for a 420-mile trip is, $19.95
Solution :
As, 20 mile distance covered by 1 gallon of gas
So, 420 mile distance covered by 
of gas
Now we have to calculate the cost of gasoline.
As, 1 gallon of gas cost = $0.95
So, 21 gallon of gas cost = 
Therefore, the cost of gasoline for a 420-mile trip is, $19.95
There is no more than 1 sigma bond between any two atoms.
Molecules with rings have supplementary sigma bonds, such as benzene rings,
which have 6 C−C
sigma bonds within the ring for 6 carbon atoms. The anthracene molecular
formula is C14H10, it has three
rings so that the rule contributes the number of sigma bonds as 24 added with 3
is 27, which will be subtracted with 1 which will give 26.
Answer:
3,116J/K
Explanation:
This question asks to calculate the entropy change of the surroundings.
To do this, we need the standard enthalpy of formation ΔfH° of the reacting species and products first:
We should observe that standard enthalpy if formation of O2 is zero. We proceed with the rest of the species.
H2CO = -109.5KJ/mol
CO2 = -393.5KJ/mol
H2O = -285.8KJ/mol
Now, we calculate the standard change of enthalpy of the reaction as:
ΔHrxn = ΔHproduct - ΔHreactant = (-285.8 - 393.5) +(109.5) = -569.8 KJ/mol
The relationship between the entropy and the standard formation enthalpy is given as
The relationship is:
ΔSosurroundings = - ( ΔHof/ T)
We convert the standard enthalpy of formation to joules first = -569.8 * 10^3 Joules
Using the formula above at a temperature of 298k, the entropy change would be:
-(-569.8 * 10^3)/298 = 1912J/K
Now, we know that 1.63 moles of H2CO reacted. We also need to know the coefficient of the H2CO in the reaction which is 1.
We thus have:
1.63 mol H2CO(g) * (1912J/K * 1 mol H2CO) = 3116J/K
A. combustion
because carbon dioxide is the main product of burning carbon based fuels and combustion is the process of burning something
Answer:
the mass of one mole of an element, or Avogadro's number (6.02 x 1023) of atoms, is equal to its atomic mass in grams. In other words, 1 amu = 1 gram/mole. So if the mass of one hydrogen atom is 1 amu, the mass of one mole of hydrogen is 1 gram.
Explanation:
