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ozzi
3 years ago
9

PLEASE ANSWER FAST!!!!! Word problem ideas for 4x+10 2(x-6)

Mathematics
1 answer:
RUDIKE [14]3 years ago
7 0

Step-by-step explanation:

Simplify 2(x-6)

2x+2•-6

2x-12

4x+10=2(×-6)=2x-12

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For A Free 50 Points... Tell me how to give an answer the "Brainliest Answer" Thingy... Also the person who answers with how to
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Answer:

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Step-by-step explanation:

               

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What is half of seven in a whole number
Nikitich [7]
0.7 / 100 = 0.007 or 0.007 x 100 = 0.7 hope this helps

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Find the surface area of a sphere with a radius of 30 m. leave your answer in terms of pi @Directrix
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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

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Advocard [28]
Lacey, because you have to do the opposite when you want to get rid of a number. She subtracted 20 because it was originally positive 20. Chris messed up and did not do the opposite, subtraction, and instead he added 20
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