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ddd [48]
3 years ago
15

Write an expression that represents the area of a circle with radius 3x^3. (For any circle with radius r, a=π r^2 = π .r .r ^.)

Mathematics
1 answer:
aalyn [17]3 years ago
6 0

9514 1404 393

Answer:

  B. 9πx^6

Step-by-step explanation:

Putting the given radius into the area formula gives ...

  A = πr^2

  A = π(3x^3)^2 = π(3^2)(x^(3·2))

  A = 9πx^6

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What decimal equivalent of 5/6
BartSMP [9]
Divide 5 by 6 to get0.8333 ( the 3 keeps repeating)
6 0
3 years ago
I need to find x. It wants me to find the indicated angle measure.
Nataliya [291]

Answer:

x=27

Step-by-step explanation:

(2x-18)+(4x)=180 bc its a straight line

simplify

6x-18=180

-18       -18

6x=162

divide

x=27

5 0
3 years ago
Read 2 more answers
162*0.967=what? {this is multiplication}
Veronika [31]

Answer:

156.654

Step-by-step explanation:

162*.967=156.654

6 0
3 years ago
Eastern Meats pays its delivery workers regular time for up to 36 hours per week and
Cloud [144]

Answer:

42-36=6

42+6=48

545.28 / 48=11.36

11.36

8 0
3 years ago
Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
3 years ago
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