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Bas_tet [7]
3 years ago
12

Can someone explain how to solve this? Thank you!!!

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

I can't see anything its black can you comment me? if you do i can help you

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Solve for x using
vlada-n [284]

Answer:

11

Step-by-step explanation:

cross multiply - 2(2x-4) = 3(x=1)

4x - 8 = 3x + 3

4x - 3x = 3 + 8

x = 11

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A local store is offering 20% off regular priceiPods. The original price is $200, how much willthe iPod cost during the sale?
Tju [1.3M]
This is the answer :
100%-20%=80%
\frac{80}{100}  =  \frac{x}{200}  \\ x =  \frac{200 \times 80}{100}  =  \frac{16000}{100}  = 160
the answer $160
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2 years ago
Jewan is setting up a monthly budget. His gross monthly income is $3125, but 20% is deducted for taxes. How much money is deduct
romanna [79]

Answer:

$625

$2500

Step-by-step explanation:

tax = percent of tax x income

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amount remaining = income - tax

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4 0
2 years ago
An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell
mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

\overline{x} = \frac{34+40+46+49+61+64}{6} = 49

Sample standard deviation:

s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.0.150

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. So

M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0
2 years ago
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