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Greeley [361]
3 years ago
12

Tasrnu unscramble pls help me unscrammble plssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss

ssssssssssssssssssssssss
Physics
2 answers:
Vika [28.1K]3 years ago
5 0
Santur -Iranian musical instrument
Saturn -the planet
Vladimir79 [104]3 years ago
3 0

Answer:

SANTUR OR ARNUTS

HOPE IT HELPS YOU

THANKS

MARK AS THE BRAINLEIST PLEASE

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Answer:

C& D

Explanation:

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A tennis ball is hit with a vertical speed of 10 m/s and a horizontal speed of 30 m/s. How far will the ball travel horizontally
sweet-ann [11.9K]

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

  • Δx = v_i * t + 1/2at²  

Let's use this equation in terms of the y-direction.

  • Δx_y = (v_i)y * t + 1/2a_y * t²

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

  • 0 m = 10 m/s * t + 1/2(-10 m/s²) * t²

Simplify the equation.

  • 0 = -10t + 5t²  
  • 0 = 5t² - 10t

Factor the equation.

  • 0 = 5t(t - 2)

Solve for t by setting both factors to 0.

  • 5t = 0
  • t - 2 = 0

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

  • Δx = v_i * t + 1/2at²
  • Δx_x = (v_i)x * t + 1/2a_x * t²

Plug the known values into the equation.

  • Δx_x = 30 m/s * 2 sec + 1/2(0 m/s²) * (2 sec)²

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

  • Δx_x = 30 * 2
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The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

4 0
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,how do charged objects react???quiet urgent
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A chemical reaction takes place in which energy is absorbed. Arrange the characteristics of the reaction in order from start to
myrzilka [38]

Let’s create a diagram that shows the chemical reaction absorb energy. Take a look at the diagram I created that is attached to this answer.


Now, the start of the graph line is pretty flat and low leveled. This is the start, which is the reactants. The beginning of a chemical reaction that absorbs energy will almost always start with reactants. I labeled this this “Start: Reactants” and colored the text light green so you can easily detect the part I’m talking about.


Moving on, we see there’s a light blue arrow pointing from the the near bottom to the top curve of the graph line. This is the where the activation energy is rising. Activation energy is the difference between the reactants and products. When the graph line begins to cure, this is when the transition state is beginning. I labeled the transition state, “Transition State” and colored the text a light orange. I colored the line a light blue and also labeled it “Activation Energy” and colored the text light blue as well. I hope it’s easy enough for you to follow along. :)


Next we see that the graph line dips and then goes flat, but it doesn’t go low leveled. It says fairly higher than where it started. This is the end product. I labeled this “End: Product” and colored the text light purple so you can easily detect it.


Okay, now that that’s clear, let’s go ahead and fill in the first blank. According to the diagram we see that the start should be a reactant, and since the graph line starts out pretty low. So, this means that the first tile should be “Low energy of reactants."


Now the second tile should definitely be “Transition State.” This is because the second part in the diagram is transition state. Again, this is mainly where the activation energy is starting to rise.


As for the last and final tile, we should chose “High energy of products.” This is because the diagram is left off on a high leveled part at the end of the graph line.


So, when you place the tiles they should look something like this.


Low energy of reactants

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