The potential across the capacitor at t = 1.0 seconds, 5.0 seconds, 20.0 seconds respectively is mathematically given as
- t=0.476v
- t=1.967v
- V2=4.323v
<h3>What is the potential across the capacitor?</h3>
Question Parameters:
A 1. 0 μf capacitor is being charged by a 9. 0 v battery through a 10 mω resistor.
at
- t = 1.0 seconds
- 5.0 seconds
- 20.0 seconds.
Generally, the equation for the Voltage is mathematically given as
v(t)=Vmax=(i-e^{-t/t})
Therefore
For t=1
V=5(i-e^{-1/10})
t=0.476v
For t=5s
V2=5(i-e^{-5/10})
t=1.967
For t=20s
V2=5(i-e^{-20/10})
V2=4.323v
Therefore, the values of voltages at the various times are
- t=0.476v
- t=1.967v
- V2=4.323v
Read more about Voltage
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Complete Question
A 1.0 μF capacitor is being charged by a 5.0 V battery through a 10 MΩ resistor.
Determine the potential across the capacitor when t = 1.0 seconds, 5.0 seconds, 20.0 seconds.
I think this fits the definition of ethical relativism. does that sound right?
Answer:
Explanation:
Given:
Mass of the boat, m = 4040 kg
The driving force of engine, FB = 4660 N in west = + 4660 N
The force of wind, Fwi = 880 N in east = -880 N
The force of water, Fwa = 1400 N in east = -1400N
Total three forces are acting on the boat
Fnet= Fb+fwi+Fwa
Fnet= 4660 - 880 - 1400
Fnet= +2380N
Acceleration (a) = Force/mass
= 2380/4040
= 0.59m/s2
You pick up the hula hoop and stand inside of it then pick it up will you’re inside it and hold to your waist and spin it then turn your hips
Try the solutions described in the attached picture, note the answers are marked with green colour.