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4 years ago

The addition of electron shells results in shielding of electrons from the nucleus.

Physics

1 answer:

Pani-rosa [81]4 years ago

4 0

Answer:

Addition of shells increases the distance of outer electrons from the nucleus.

Explanation:

Shielding effect is known as the attraction between the nucleus and an electron of any atom. In other words, it is the reduction in effective nuclear charge on an electron cloud.

Addition of electron shells results in the shielding of electron from nucleus. As the number of electron shells increases then farther will be the electrons placed from the nucleus and hence it will become easier to expel the electrons from outer shells with only little amount of ionization energy.

So, the amount of ionization energy require will be indirectly proportional to the shielding effect because more the shielding of electrons from the nucleus less will be the ionization energy require to expel the electrons.

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If two objects are moved closer together so that the distance between them is one-third the original distance, what is the gravi

r-ruslan [8.4K]

Answer:
nine times the original gravitational force
Explanation:
The rule of the gravitational force between two bodies is shown in the attached images.
The parameters in the rule are:
Fg : the gravitational force between the two bodies
G : universal gravitational constant
m1 and m2 : the masses of the two bodies
r : the distance between the two bodies

From the given rule, we can notice that:
The force of attraction between the two bodies is inversely proportional to the square of the distance between them.
This means that:
As the distance decreases to 1/3 its original value, the gravitational force would increase by a factor of 9.

Hope this helps :)

3 0

3 years ago

Read 2 more answers

A sled of mass m is coasting on the icy surface of a frozen river. While it is passing under a bridge, a package of equal mass m

sweet [91]

Answer:B

Explanation:

Given

mass of Sled is m

another package of mass m is thrown on it

Suppose u be the initial velocity of sled

conserving momentum

$mu=2mv$

$v=\frac{u}{2}$

where v is the final velocity

Initial kinetic energy $=\frac{1}{2}mu^2$

Final Kinetic Energy $=\frac{1}{2}(2m)\cdot (\frac{u}{2})^2$

Final Kinetic Energy $=\frac{1}{2}\times \frac{1}{2}mu^2$

Final kinetic Energy is half of initial

5 0

3 years ago

A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur

daser333 [38]

The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

$H = \frac{nI}{l}$

Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

$n = \frac{Hl}{I}$

The magnetic field is again given by,

$H = \frac{B}{\mu_t}$

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

$n = \dfrac{\frac{B}{\mu_t}l}{I}$

Replacing with our values we have that,

$n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}$

$n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}$

$n = 27.5 \approx 28$

Therefore the number of turn required is 28Truns

4 0

4 years ago

g A The box leaves position x=0 with speed v0. The box is slowed by a constant frictional force until it comes to rest at positi

CaHeK987 [17]

Answer:

fr = m v₀² / 2 (x₁-x₀)

Explanation:

a) For this exercise we use Newton's second law

X axis

- fr = ma

Y Axis

N-W = 0

N=W

let's look for acceleration with expressions of kinematics

v² = v₀² - 2 a Δx

at the point where stop v = 0

a = v₀² / 2 Δx

let's replace

-fr = m (- v₀² / 2 (x₁-x₀))

fr = m v₀² / 2 (x₁-x₀)

b)they ask for the same

in this case part of rest

v₁² = 0 + 2 a Δx

a = v₁² / 2ΔX

we write Newton's second law

F - fr = m a

fr = F - ma

fr = F - m v₁² / 2Δx

3 0

4 years ago

Determine the value of the force exerted by the surface (normal force) on a

Advocard [28]

Answer:

53.5 N

Explanation:

Vertical component of the F force 50 sin30 = 25 N upward

force of gravity = m g = 8 * 9.81 =78.5 N Downward

NET downward force by block on table = net upward force exerted by table = 78.5 -25 =53.5 N

8 0

2 years ago