To find the value of p, isolate/get the variable "p" by itself in the equation:
19 = 4p - 5 Add 5 on both sides
19 + 5 = 4p - 5 + 5
24 = 4p Divide 4 on both sides to get "p" by itself
6 = p Your answer is B
PROOF
19 = 4p - 5 Substitute/plug in 6 into "p" since p = 6
19 = 4(6) - 5
19 = 24 - 5
19 = 19
<span>3.19459 seconds
Since we've been given the equation for how high the ball is at t seconds, all we need to do is solve for a height of 0. So
h = 67 - 5t - 5t^2
0 = 67 - 5t - 5t^2
And you should immediately notice that we have a quadratic equation with A = -5, B = -5, and C=67. Use the quadratic formula to determine the roots of -4.19459 and 3.19459. Since we can't have negative seconds, that means that the ball will hit the ground 3.19459 seconds after it was thrown.</span>
The slope is -8 and the y-intercept is (0,11) I think lol
2(x + 7) - 1 > 15 3(x + 2) < 2x + 7
2x + 14 - 1 > 15 3x + 6 < 2x + 7
2x + 13 > 15 3x - 2x < 7 - 6
2x > 15 - 13 x < 1
2x > 2
x > 2/2
x > 1
so, x > 1 OR x < 1.....all real numbers except 1