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3 years ago

9

The density of mercury is 13600 kg/m3 at 0°C. what is its density at temperature 100°C

1 answer:

stealth61 [152]3 years ago

8 0

Answer:

13700 kg÷m2

Explanation:

100c+13600kg÷m2

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Explain the purpose of a geologic time scale

son4ous [18]

Geologic time scales are essential tools for geologists and biologists alike because they help show the history of the entire world in terms of relationships between different plate movements.

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3 years ago

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Give atleast (5) etypes of cleaning tools , equipment,supplies, and materials that you can find either in your home or school. I

ivanzaharov [21]

Answer and Explanation:

Cleaning tools, equipment, supplies, and materials that can be easily found in a school in one each are: scrub brush, sponges, buckets and brooms.

These equipments are essential to promote a clean, organized and safe environment and for this reason, they can be easily found both at school and in a home, since the cleanliness of these two places is essential for the well-being, proactivity and health of the people who attend them.

3 0

3 years ago

The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated

TiliK225 [7]

The age of the bone is 45840 years.

We'll begin by calculating the number of half-lives that has elapsed.

Amount remaining (N) = 0.3125 g

Initial amount (N₀) = 80 g

<h3>Number of half-lives (n) =? </h3>

N × 2ⁿ = N₀

0.3125 × 2ⁿ = 80

Divide both side by 0.3125

2ⁿ = 80 / 0.3125

2ⁿ = 256

2ⁿ = 2⁸

<h3>n = 8</h3>

Thus, 8 half-lives has elapsed

Finally, we shall determine the age of the bone.

Half-life (t½) = 5730 years

Number of half-lives (n) = 8

<h3>Time (t) =? </h3>

t = n × t½

t = 8 × 5730

<h3>t = 45840 years </h3>

Therefore, the age of the bone is 45840 years.

Learn more on half-life: brainly.com/question/15900105

5 0

3 years ago

A 40.0-μFcapacitor is connected across a 60.0 Hz generator. An inductor is then connected in parallel with the capacitor. What i

amm1812

Answer:

The value of the inductance is 175.9 mH.

Explanation:

Given that,

Capacitor $C= 40.0\ \muF$

Frequency = 60.0 Hz

The inductor and capacitor is connected in parallel, the voltage across each of these elements is the same.

We have,

$V_{L}=V_{C}$

Using ohm's law

$I_{rms}\times X_{L}=I_{rms}\times X_{C}$

$X_{L}=X_{C}$

$2\pi f L=\dfrac{1}{2\pi f C}$

$L=\dfrac{1}{4\pi^2\times f^2\times C}$

Put the value into the formula

$L=\dfrac{1}{4\times\pi^2\times60.0^2\times40\times10^{-6}}$

$L=0.1759\ H$

$L=175.9\times10^{-3}\ H$

$L=175.9\ mH$

Hence, The value of the inductance is 175.9 mH.

5 0

4 years ago

An alpha particle (charge = +2.0e) is sent at high speed toward a gold nucleus (charge = +79e). What is the electric force actin

umka2103 [35]

Answer:

F = 91.27 N

Explanation:

Parameters given:

Charge of alpha particle, q = +2.0e = $2.0 * 1.60217662 * 10^{-19}$ = $3.204 * 10^{-19} C$

Charge of gold nucleus, Q = +79e = $79 * 1.60217662 * 10^{-19}$ = $1.266 * 10^{-17} C$

Distance between the alpha particle and gold nucleus, r = $2.0 * 10^{-14} m$

Electric force is given as:

F = $\frac{kqQ}{r^2}$

where k = Coulomb's constant

Therefore:

$F = \frac{9 * 10^9 * 3.204 * 10^{-19} * 1.266 * 10^{-17}}{(2.0 * 10^{-14})^2} \\\\\\F = 91.27 N$

The electric force acting on the alpha particle when the alpha particle is $2.0 * 10^{-14} m$ from the gold nucleus is 91.27 N.

7 0

3 years ago