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Firdavs [7]
3 years ago
15

Convert 68852 millijoules into Calories. (Write your answer in the decimal form. Do not include units in your answer).

Physics
1 answer:
alex41 [277]3 years ago
6 0

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories

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Which property does not apply to a motor? A. It uses an electromagnet. B. The direction of current changes twice during the rota
Rufina [12.5K]

Answer:  

     

Explanation:

A motor converts electrical energy to mechanical energy. A current carrying coil is placed between electromagnets. A magnetic force is exerted on the coil which makes it rotate. The direction of current changes twice during the rotation of the coil. An outside source of electric current is used.

Thus, the wrong statement is D. It converts mechanical energy into electrical energy. It is the generator which converts mechanical energy into electrical energy.

3 0
3 years ago
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Light with a wavelength of 400 nm strikes the surface of cesium in a photocell, and the maximum kinetic energy of the electrons
Firdavs [7]

Answer:

The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

Explanation:

Given that,

Wavelength = 400 nm

Energy E=1.54\times10^{-19}\ J

We need to calculate the longest wavelength of light that is capable of ejecting electrons from that metal

Using formula of energy

E = \dfrac{hc}{\lambda}

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{1.54\times10^{-19}}

\lambda=1292\times10^{-9}\ m

\lambda=1292\ nm

Hence, The longest wavelength of light that is capable of ejecting electrons from that metal is 1292 nm.

8 0
3 years ago
Name three categories that are used to classify the elements in the periodic table?
nikitadnepr [17]

Answer:

metals,nonmetals, and inert gases

Explanation:

6 0
3 years ago
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What was the direction of the ball’s velocity
Tju [1.3M]

Part of the question is missing. Here it is:

<em>A 72 g autographed baseball slides off of a 1.3 m high table and strikes the floor a horizontal distance of 0.7m away from the table.     The acceleration of gravity is 9.81 m/s2. What was the direction of the ball’s velocity  just before it hit the floor? </em>

Answer:

\theta=-75.7^{\circ}

Explanation:

The motion of the ball is a projectile motion, which consists of two separate motions:

- A horizontal motion at constant velocity

- A vertical motion at constant acceleration (free fall)

We start by analyzing the vertical motion, to find the time of flight of the ball. This can be done by using the suvat equation

s=ut+\frac{1}{2}at^2

where, choosing downward as positive direction:

s =1.3 m is the vertical displacement of the ball

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time

Solving for t,

t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(1.3)}{9.8}}=0.52 s

Now we can find the final vertical velocity of the ball, using:

v_y=u+at

And susbtituting t = 0.52 s, we find

v_y = 0 +(9.8)(0.52)=5.1 m/s

It is important to keep in mind that the direction of this velocity is downward, since we chose downward as positive direction.

The horizontal velocity of the ball instead is constant; we know that the ball covers a horizontal distance of

d = 0.7 m

In a time of

t = 0.52 s

So, the horizontal velocity is

v_x = \frac{0.7}{0.52}=1.3 m/s

So now we can find the direction of the ball's velocity using:

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{5.1}{1.3})=75.7^{\circ}

And since the vertical direction is downward, this means that this velocity is below the horizontal, so the answer is

\theta=-75.7^{\circ}

8 0
3 years ago
11. a 0.12-kg, 50-cm-long uniform bar has a small 0.055-kg mass glued to its left end and a small 0.11-kg mass glued to the othe
Eduardwww [97]

The left end should the fulcrum be placed is 29.8 cm.

What is fulcrum?
The lever's pivot point is known as a fulcrum. You probably first came across a fulcrum on the playground, directly beneath the see-saw. Any general prop as well as support was referred to as a fulcrum in the 17th century. Thanks to physics class, it now has more scientific connotations. However, the term "fulcrum" is still frequently used to refer to something that is central to an event or activity, as in "the fulcrum of a debate." Who is the father who arranges everyone's playdates? He serves as the focal point of the playground social group.

counter clockwise moments = clockwise moments
(0.055 kg * x) + (0.120*(x-25)) = 0.110 kg * (50-x)
                  0.055x + 0.12x - 3 = 5.5 - 0.11x
                                              x = 29.8 cm

To learn more about fulcrum
brainly.com/question/28320996
#SPJ4

7 0
1 year ago
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