A billiard ball rolls from rest down a smooth ramp that is 8.0 m long. the acceleration of the ball is constant at 2.0?

Two velocity vectors, one is twice of the other, and separated by 90 Degree angle. If their resultant is calculated 90 m/s, what

Artyom0805 [142]

Answer:

Vy = 80.5 [m/s]

Explanation:

In order to solve this problem we must use the Pythagorean theorem.

V = 90 [m/s]

The components are Vx and Vy:

Therefore:

$v=\sqrt{v_{x}^{2} + v_{y}^{2} }$

where:

Vy = 2*Vx ; because one is twice of the other.

$90 = \sqrt{v_{x}^{2} +(2*v_{x})^{2} }\\ 90 =\sqrt{v_{x}^{2}+4*v_{x}^{2}} \\90 =\sqrt{5v_{x}^{2}} \\90=2.23*v_{x} \\v_{x}=40.25[m/s]$

and the bigger vector is:

Vy = 40.25*2

Vy = 80.5 [m/s]

3 0

3 years ago

Which of the following factors are involved in explaining why the energy of orbitals within a principle quantum level in multiel

Citrus2011 [14]

It looks like you have missed the necessary options for us to answer this question so I had to look for it. Anyway, here is the answer generally as the ℓ quantum number increases the energy is slightly higher. As a result 2s and 2p are no longer identical in energy in atoms<span> with more than one electron.</span>

Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

4 0

3 years ago

Item 8 The cost (in dollars) of making b bracelets is represented by 4 5b. The cost (in dollars) of making b necklaces is repres

grin007 [14]

Answer:

3b+2

Explanation:

First your question has so many mistakes

What I understand

bracelets cost 4+5b

necklaces cost 8b+6

First we have to make an equaion

=(8b+6)-(4+5b)

simplify it

=8b+6-4-5b

=3b+2 Answer

4 0

3 years ago

Suppose that a charged particle of diameter 1.00 micrometer moves with constant speed in an electric field of magnitude 1.00×105

Gnesinka [82]

Answer:

Q1 = 7.25*10^(-16) C

Explanation:

We are given;

electric field strength = (1 x 10^5 N/C

drag force (F) = 7.25 x 10^(-11) N

The question says it's moving with constant velocity. This means that he particle is in equilibrium and not accelerating.

Columbs law force of attraction or repulsion between two charges is given as;

F=(KQ1Q2)/r²

Now, electric field strength is given as the formula;(K*Q2)/r², thus plugging the relevant values gives us;

7.25 x 10^(-11) N= (1 x 10^(5) N/C)Q1 Q1 = 7.25 x 10^(-11) /(1 x 10^(5))

Q1 = 7.25*10^(-16) C

5 0

3 years ago

Read 2 more answers

2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or

krek1111 [17]

a) The work done by the tree is $-1.44\cdot 10^5 J$

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

$W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2$

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

$W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J$

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

$W=Fd$

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

$W=-1.44\cdot 10^5 J$ is the work done

$d=50.0 cm = 0.50 m$ is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

$F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N$

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

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3 0

4 years ago