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lawyer [7]
3 years ago
14

one layer of earth's atmosphere is called the stratosphere. At one point above earth's surface the stratosphere extends from an

altitude of 16 km to an altitude of 50 km. Write a compound inequality to show the altitudes that are within the range of the stratosphere. (please show work! i really need to know how to figure out these word problems. thanks!)
Physics
2 answers:
masya89 [10]3 years ago
8 0

According to all the given requirements 

stratosphere x starts at an altitude of 16 km

that means  

<span>16≤x

</span> and,as given ,stratosphere ends at an altitude of 30 km:
which means
<span>x≤30</span> combining both of them we get

<span>16≤x≤30</span> So the range of the stratosphere is from 16 to 30 km. 

Agata [3.3K]3 years ago
3 0

Answer:

The Stratosphere layer is the layer next to the troposphere and it extends from an elevation of about 10-15 km to 50-60 km above the surface of earth. In this layer, the temperature increases with the increasing height. This increase in temperature is because of the presence of the ozone. This ozone is also called good ozone as it protects the lives on earth from the harmful ultraviolet radiations emitted from the sun.

In order to show the elevation range of the stratosphere layer, in the form of compound inequalities, we take two equations from the given data-

=> X ≥ 16 -------- (equation 1), where X= thickness of the stratosphere layer.

=> X ≤ 50 -------- (equation 2)

Now, from equation 1 and equation 2, we have,

=> 16 ≤ X ≤ 50

So, in conclusion, we can say that the thickness of stratosphere ranges from 16 to 50 km.

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If 1 foot is 30.28 centimeters.how many cm is 130 feet
uranmaximum [27]

Answer:3,936.4

Explanation:

If 1 foot is 30.28 centimeters multiply 30.28 by 130

6 0
4 years ago
A combination of two identical resistors connected in series has an equivalent resistance of 12. ohms. What is the equivalent re
SIZIF [17.4K]

Answer:

R1 + R2 = R = 12 for resistors in series - so R1 = R2 if they are identical

2 R1 = 12         and R1 = R2 = 6 ohms

1 / R = 1 / R1 + 1 / R2     for resistors in parallel

R = R1 * R2 / (R1 + R2) = 6 * 6 / (6 + 6) = 3

The equivalent resistance would be 3 ohms if connected in parallel

7 0
3 years ago
A 80 ohms resistor, 0.2 H inductance and 0.1 mF capacitor are connected in series across a generator (60 Hz, V rms=120 V). Deter
qaws [65]

Answer:

Impedance = 93.75 ohms

Current = 1.81 A

Explanation:

Resistance = R = 80 ohms

Inductance = L = 0.2 H

Inductive reactance = XL = X_{L}= = ωL = (2πf) L

= 2 (3.14) (60)(0.2) = 75.398 Ohms

Capacitive reactance = 1 / ωC = 1/(2πf)C = 1 / [(2π)(60)(0.1 × 10⁻3)]

= 26.526 Ohms  

Impedance = Z = \sqrt{R^{2} + (X_{L} - X_{C})^{^{2}}} =

= \sqrt{8788.511} = 93.747 ohms  

Voltage = \sqrt{2} × 120 = 169.7056 V

Current = I = V ÷ R = (169.7056) ÷ 93,747 = 1.81 A

8 0
3 years ago
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.680 Hz. The pendulum ha
sineoko [7]

Answer:

Therefore, the moment of inertia is:

I=0.37 \: kgm^{2}

Explanation:

The period of an oscillation equation of a solid pendulum is given by:

T=2\pi \sqrt{\frac{I}{Mgd}} (1)

Where:

  • I is the moment of inertia
  • M is the mass of the pendulum
  • d is the distance from the center of mass to the pivot
  • g is the gravity

Let's solve the equation (1) for I

T=2\pi \sqrt{\frac{I}{Mgd}}

I=Mgd(\frac{T}{2\pi})^{2}

Before find I, we need to remember that

T = \frac{1}{f}=\frac{1}{0.680}=1.47\: s

Now, the moment of inertia will be:

I=2*9.81*0.340(\frac{1.47}{2\pi})^{2}  

Therefore, the moment of inertia is:

I=0.37 \: kgm^{2}

I hope it helps you!

7 0
3 years ago
In an isolated system, Bicycle 1 and Bicycle 2, each with a mass of 10 kg,
dimulka [17.4K]

Answer: 20 kgm/s

Explanation:

Given that M1 = M2 = 10kg

V1 = 5 m/s , V2 = 3 m/s

Since momentum is a vector quantity, the direction of the two object will be taken into consideration.

The magnitude of their combined

momentum before the crash will be:

M1V1 - M2V2

Substitute all the parameters into the formula

10 × 5 - 10 × 3

50 - 30

20 kgm/s

Therefore, the magnitude of their combined momentum before the crash will be 20 kgm/s

7 0
3 years ago
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