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grin007 [14]
3 years ago
15

I need help ASAP ..................................

Physics
2 answers:
Travka [436]3 years ago
6 0
It’s dust srry if I am late
jek_recluse [69]3 years ago
6 0
It’s dust. looks like you got already
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Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Earth he is moving at 60 m/s
Andrej [43]

Answer:

  Potential energy = 73.575 kJ

  Kinetic energy = 135kJ

  Total mechanical energy = 208.575 kJ

Explanation:

   The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

  The kinetic energy of a body is given by KE=\frac{1}{2} mv^2, where v is the velocity and m is the mass of body.

  Total mechanical energy = Kinetic energy + Potential energy

  KE=\frac{1}{2} mv^2=\frac{1}{2} *75*60^2= 135000J = 135kJ

  PE = mgh = 75*9.81*100 = 73575 J = 73.575 kJ

  Total mechanical energy = Kinetic energy + Potential energy = 135+73.575

                                             = 208.575 kJ    

4 0
3 years ago
When a potassium atom forms an ion, it loses one electron. What is the electrical charge of the potassium ion? *
Ganezh [65]
+1 An electron has a negative charge so losing a charge of -1 from an uncharged, or neutral, atom will leave an ion with a positive charge.
5 0
4 years ago
Read 2 more answers
What is the mass number of the isotope lithium-7?
NNADVOKAT [17]
<span>the answer is 7...What is the mass number of the isotope lithium-7? the mass of isotope lithium-7 is 7. </span>
5 0
3 years ago
Read 2 more answers
The two forces of a 3rd law pair always act on different bodies. The two forces of a 3rd law pair always act on different bodies
svetoff [14.1K]

1. The two forces of a 3rd law pair always act on different bodies.

TRUE

SO above statement is TRUE because Newton's III law is valid for two different objects where one object will exert force and other body will exert reaction force on it.

2. Part F Given that two bodies interact via some force, the accelerations of these two bodies have the same magnitude but opposite directions. (Assume no other forces act on either body.)

FALSE

This is false because the force of action and Reaction is same on two different objects but for finding acceleration we need to divide the force by mass of two objects and since the mass of two bodies may be different so we can say that acceleration may be different.

3. Part G According to Newton's 3rd law, the force on the (smaller) moon due to the (larger) earth is

(i) greater in magnitude and antiparallel to the force on the earth due to the moon.

(ii) greater in magnitude and parallel to the force on the earth due to the moon.

(iii) equal in magnitude but antiparallel to the force on the earth due to the moon.

(iv) equal in magnitude and parallel to the force on the earth due to the moon.

(v) smaller in magnitude and antiparallel to the force on the earth due to the moon.

(vi) smaller in magnitude and parallel to the force on the earth due to the moon.

Since Earth and moon is an isolated system so here Newton's III law is valid due to which we can say that two forces are equal in magnitude but opposite in sign

so correct answer will be

equal in magnitude but antiparallel to the force on the earth due to the moon.

4 0
3 years ago
4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not
vampirchik [111]

The ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

f = \frac{c}{\lambda}

where

f is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

\lambda is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz

For the UVB, the range of wavelength is 280 nm - 320 nm, so

\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m

So the corresponding frequencies are

f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz

So the ranges of frequency are:

UVA: [7.50-9.38]\cdot 10^{14} Hz

UVB: [9.38-10.71]\cdot 10^{14} Hz

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0
3 years ago
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