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steposvetlana [31]
3 years ago
14

Solve x^2—y=—2 —x+y=4 using the elimination method

Mathematics
1 answer:
wariber [46]3 years ago
5 0
X² - y = -2  .................. equation 1
<u>-x + y = 4</u>  .................. equation 2      from the y's  we can obtain y - y = 0
the new equation will be
x² - x = 2      to for a quadratic equation make the equation equals to zero
x² - x - 2 = 0
x² - 2x + x - 2 = 0       using factorization method
x(x - 2) + 1(x - 2) = 0
(x + 1)(x - 2) = 0
x + 1=0   and  x - 2=0
x = -1 or 2
 subtitute x= -1 in equation 2                     subtitute x= 2 in equation 2
-(-1) + y = 4                                                  -(2) + y = 4 
1 + y = 4                                                       -2 + y = 4 
y= 4 - 1                                                          y= 4 + 2
y= 3                                                                y= 6

the values of x are -1 and 2 . The values of y are 3 and 6
when x is -1, y is 3
when x is 2, y is 6...
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Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

3 0
3 years ago
Geometry: fill in the blanks (ASAP!! It’s urgent)
stepladder [879]

5. m∠C = 95°

6. m∠C = 70°

7. The other acute angle in the right triangle = 70°

8. m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 110°

11. m∠B = 70°

12. m∠Z = 70°

<h3>What are Triangles?</h3>

A triangle is a 3-sided polygon with three sides and three angles. The sum of all its interior angles is 180 degrees. Some special triangles are:

  • Isosceles triangle: has 2 equal base angles.
  • Equilateral triangle: has three equal angles, each measuring 60 degrees.
  • Right Triangle: Has one of its angles as 90 degrees, while the other two are acute angles.

5. m∠C = 180 - 50 - 35 [triangle sum theorem]

m∠C = 95°

6. m∠C = 180 - 25 - 85 [triangle sum theorem]

m∠C = 70°

7. The other acute angle in the right triangle = 180 - 90 - 25 [triangle sum theorem]

The other acute angle = 70°

8.  m∠C = 180 - 55 - 55 [isosceles triangle]

m∠C = 70°

9. m∠C = 60° [equilateral triangle]

10. Measure of the exterior angle at ∠C = 50 + 60

Measure of the exterior angle at ∠C = 110°

11. m∠B = 115 - 45

m∠B = 70°

12. m∠Z = 180 - 35 - 75

m∠Z = 70°

Learn more about triangles on:

brainly.com/question/25215131

#SPJ1

8 0
2 years ago
What does it take to be a friend?
dangina [55]

Answer:You need to be nice

Or just be you own way

But be nice

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
What is the solution to the system of equations?<br> O (-4,1)<br> O (-2, 1)<br> O (1.4)<br> O (1,-2)
Tcecarenko [31]

Answer:

<em></em>(1,-2)<em></em>

<em></em>

Step-by-step explanation:

Given

The attached graph

Required

Determine the solution

The solution here is the intersection points of the two lines. From the attachment, both lines meet

x = 1

y = -2

<em>Hence, the solution is: </em>(1,-2)<em></em>

3 0
3 years ago
It took Miguel 7 mins 38 secs to run one mile. It took Jorja 9mins 13 secs to run one mile. How many more seconds did it take to
ExtremeBDS [4]
38-13=25 more secs. bc ur just dealing with the sec. not min so... just subtract
7 0
3 years ago
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