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3 years ago

Solve this equation -8-x=x-4x

Mathematics

1 answer:

almond37 [142]3 years ago

4 0

Answer:

x=4

Step-by-step explanation:

-8-x=x-4x

Combine like terms

-8 -x =-3x

Add x to each side

-8 -x+x = -3x+x

-8 = -2x

Divide each side by -2

-8/-2 = -2x/-2

4 = x

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The deepest part of the Mariana trench (the deepest trench in the world’s oceans) is at an elevation of -11.033 kilometers. The

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

-2.968

8 0

3 years ago

The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rate r.

Virty [35]

A = P + SI

A-P = SI

5425-5000 = 425

THEREFORE THE SIMPLE INTRESTE IS $425

SI = PTR/100

425 = 5000×1×R/100

425×100/5000×1=R

425×100÷5,000×1 = 8.5%

THEREFORE THE RATE IS 8.5%

8 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago

Need help!

siniylev [52]

Correct Inputs :-

In ΔABC right angled at A, D and E are points on BC, C such that BD = CD and AD ⊥ BC

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ Let us know about definition of altitude first. The altitude of a triangle is the perpendicular line segment drawn from the vertex to the opposite side of the triangle.

$\leadsto$ Median is the line segment from a vertex to the midpoint of the opposite side.

Let us Check all options one by one

CD is line segment which starts from vertex C but don't falls on opposite side AB thus it is not an altitude.❌

BA is line segment which starts from vertex B and falls perpendicularly on opposite sides AC and is thus an altitude.✔️

AD is line segment which starts from vertex A and falls perpendicularly on opposite side BC and is thus an altitude.✔️

AE is a line segment which starts from vertex A but doesn't falls perpendicularly on opposite side BC and is thus not an altitude.❌

AD falls on BC with D as mid point because BD = CD and is thus a median. ✔️

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2 years ago

Brittany was tracking the increasing temperature in the morning. At 8 a.m., it was 68 degrees Fahrenheit. At 10 a.m., it was 74

AysviL [449]

Im gonna go with A..

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3 years ago