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konstantin123 [22]
2 years ago
12

Lol 2 meter per seconds per seconds per seconds per seconds per seconds per seconds per seconds per seconds per seconds per seco

nds per seconds per seconds per seconds per seconds per seconds per seconds per seconds
Physics
2 answers:
GenaCL600 [577]2 years ago
7 0

Answer:

ok

Explanation:

Dima020 [189]2 years ago
3 0

Answer:should i continue ?

Explanation:

Second per second second per second second per second seconds per seconds seconds per seconds seconds per seconds seconds pers lol seconds per seconds seconds per seconds and on lol

S

Sorry but ty for the points

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As the result of a thermal inversion the prevailing air temperature profile increases 1°C/100m above the ground level. To what m
astra-53 [7]

Answer:

909.1 m

Explanation:

Rate of temperature increase with 100 m elevation = 1°C

h = Maximum Height

Adiabatic lapse rate = -0.65°C/100 m

We have the relation

\dfrac{1^{\circ}C}{100}=\dfrac{15^{\circ}C}{h}+\left(-\frac{0.65}{100}\right)\\\Rightarrow \dfrac{1^{\circ}C}{100}+\left(-\frac{0.65}{100}\right)=\dfrac{15^{\circ}C}{h}\\\Rightarrow h=\dfrac{15^{\circ}C}{1.65^{\circ}C}\times 100\\\Rightarrow h=909.1\ m

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3 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

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m is the man's mass

g is the gravitational acceleration

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In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
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Answer:

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Explanation:

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3 years ago
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Plz help!!!
shtirl [24]

Answer:

I think the answer to your question is true

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