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Helga [31]
3 years ago
5

sound transfers energy through solid liquid and gas what does ocean waves transfer energy through is it water or water and air a

s evaporation
Physics
1 answer:
trapecia [35]3 years ago
7 0
Hears the answer is endocytosis. <span />
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Suppose you found a mineral crystal that looked like topaz. what two minerals could you use in a scratch test to help determine
Vesna [10]
The two most important minerals you need to do the test are <span>Corundum and quartz. You use that to do scratch test</span>
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3 years ago
The mass number of iodine is 126, and it’s in the 53rd place in the periodic table. It has
Yuri [45]
It has 52 Protons and 73 Neutrons
7 0
3 years ago
A student is considering doing a complete repeated measures design experiment involving motor skills. The student's advisor has
Lelu [443]

Answer:

<em>c. ABBA counterbalancing </em>

Explanation:

The student should not use the method because it is a progressive error management technique for each subject by introducing all <em>treatment circumstances twice, first in one sequence, then in the other (AB, BA) by subject counterbalancing.</em>

If participants experience conditions more than once, they experience the conditions first in one order, then the opposite order.

3 0
3 years ago
A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
Ghella [55]

Fibers of the sweater lose electrons because electrons are leave it.

One of the ways of charging a body is by friction. Charges are transferred from one body to another when an object is rubbed against another. This is charging by friction.

A sweater has negative charges hence when the balloon is rubbed against the sweater, fibers of the sweater lose electrons because electrons are leave it.

Learn more: brainly.com/question/830809

4 0
2 years ago
Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
vlabodo [156]

To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

\omega = \frac{v}{R}

Where,

\omega =Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

\alpha = \frac{\omega}{t}

Where

\alpha =Angular acceleration

\omega = Angular velocity

t = Time

Our values are

v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})

v = 16.67m/s

r = 0.25m

t=6s

Replacing at the previous equation we have that the angular velocity is

\omega = \frac{v}{R}

\omega = \frac{ 16.67}{0.25}

\omega = 66.67rad/s

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

\alpha = \frac{\omega}{t}

\alpha = \frac{66.67}{6}

\alpha = 11.11rad/s^2

Therefore the angular acceleration of a point on the outer edge of the tires is 11.11rad/s^2

5 0
3 years ago
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