It is false because seven electrons is a characteristic of the halogen elements
Answer : The pH of a 0.1 M phosphate buffer is, 6.86
Explanation : Given,

Concentration of acid = 0.1 M
Concentration of conjugate base (salt) = 0.1 M
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now put all the given values in this expression, we get:


Therefore, the pH of a 0.1 M phosphate buffer is, 6.86
Answer:
H2SO4 ( Sulfuric Acid ) + NaOH ( Sodium Hydroxide ) > Na2SO4 ( Sodium Sulfate ) + H2O ( Water )
Explanation:
there is no image so there's no way for me to know an answer
I believe it is D because it is giving data about the garlic while the other answers are observations of the garlic