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Natali [406]
4 years ago
6

A student does an experiment to determine the molar solubility of lead(II) bromide. She constructs a voltaic cell at 298 K consi

sting of 0.733 M lead nitrate solution and a lead electrode in the cathode compartment, and a saturated lead bromide solution and a lead electrode in the anode compartment. If the cell potential is measured to be 5.45×10-2 V, what is the molar solubility of lead bromide at 298 K determined in this experiment?
Chemistry
1 answer:
attashe74 [19]4 years ago
7 0

Answer:

The molar solubility of lead bromide at 298K is 0.010 mol/L.

Explanation:

In order to solve this problem, we need to use the Nernst Equaiton:

E = E^{o} - \frac{0.0591}{n} log\frac{[ox]}{[red]}

E is the cell potential at a certain instant, E⁰ is the cell potential, n is the number of electrons involved in the redox reaction, [ox] is the concentration of the oxidated specie and [red] is the concentration of the reduced specie.

At equilibrium, E = 0, therefore:

E^{o}  = \frac{0.0591}{n} log \frac{[ox]}{[red]} \\\\log \frac{[ox]}{[red]} = \frac{nE^{o} }{0.0591} \\\\log[red] =  log[ox] -  \frac{nE^{o} }{0.0591}\\\\[red] = 10^{ log[ox] -  \frac{nE^{o} }{0.0591}} \\\\[red] = 10^{ log0.733 -  \frac{2x5.45x10^{-2}  }{0.0591}}\\\\

[red] = 0.010 M

The reduction will happen in the anode, therefore, the concentration of the reduced specie is equivalent to the molar solubility of lead bromide.

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4 0
4 years ago
2.5 piece of lithium is dropped into a 500 g sample of water at 22.1 C.ten temperature of the water increases to 23.5 C. How muc
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Answer:

2.6 kJ  

Explanation:

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3 0
4 years ago
How many times higher is the concentration of H+ in the Hubbard Brook sample than in unpolluted rainwater?
Anna [14]

Answer:

1. 7 (a neutral solution)

Answer: 10-7= 0.0000001 moles per liter

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Answer: 10-5.6 = 0.0000025 moles per liter

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Answer: 10-3.7 = 0.00020 moles per liter

The concentration of H+ in the Hubbard Brook sample is 0.00020/0.0000025, which is 80 times higher than the H+ concentration in unpolluted rainwater.

Explanation:

8 0
3 years ago
An unknown gas is found to diffuse through a porous membrane 4.11 times more slowly than h2 what is the molecular weight of the
kirill [66]
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5 0
3 years ago
Read 2 more answers
BEST GETS BRAINLIEST!!
tatuchka [14]
Gee.  I'll have to guess at what's "commonly thought".

One thing is the scale.  Nobody has an accurate picture of the scale in
his head, because we never see a true-scale drawing.  THAT's because
it's almost impossible to draw one on paper.

Example:
Shrink the solar system and everything in it so that the Sun
is the size of a quarter (the 25¢ coin).
Then:
-- The Earth is in orbit around the sun, 8.6 feet from it. 
That's close enough that you might think you could find the
shrunken Earth.  Unfortunately, it's only 0.009 inch in diameter.

-- The shrunken Jupiter is a 'huge' gas giant almost 0.1 inch in diameter.
It's orbiting the sun, about 45 feet away from it.

-- The shrunken Uranus is another gas giant, about 0.035 inch in diameter.
It's orbiting the sun, about 165 feet away from it.

-- The nearest star outside of the solar system is 441 MILES away !
On the same shrunken scale !
And there's NOTHING between here and there !  

I think that's the biggest point to make about the REAL solar system ...
its utter emptiness.  With the sun reduced to something you can hold
in your hand, the planets are the size of grains of sand, with hundreds
of feet of nothingness between them.

Same for its mass:  The solar system is approximately nothing but a star.
That's it.  A star, with some dust and some gas around it, and here and there
in the neighborhood a microscopic pebble or a chip of mineral.  But mostly
it's nothing but a star ... if you went around and gathered up all that other
rubbish in the same bag and called it a part of the same solar system, the
sun would still have more than 99% of the total mass, and the bag would
hold less than 1% of it.

Book ... It's getting late, Hillary's fading, and that's all I can think of.
I hope this much is some help.
3 0
3 years ago
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