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3 years ago

A line contains the points (82, −96) and (87, −86).

Mathematics

1 answer:

Sauron [17]3 years ago

5 0

Answer:

The slope is 2.

Step-by-step explanation:

ΔX = X2 - X1 = 87 - 82 = 5

ΔY = Y2 - Y1 = -86 - (-96) = -86 + 96 = 10

ΔY/ΔX = 10/5 = 2/1 = 2

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Restaurants A, B, C, and D lie on a circular lake. Restaurants A and Care near the

DaniilM [7]

Answer:

Step-by-step explanation:

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3 years ago

Convert from radians to degrees. Show all work. You can type pi for the symbol 7/12 pi

mariarad [96]

Answer:

The answer is $\frac{7\pi }{12}^{c}=105^{0}$

Step-by-step explanation:

The expression is

$\frac{7\pi }{12}^{c}\\= \frac{7\pi }{12}*\frac{180}{\pi }^{0} \,;[1^{c}=\frac{180}{\pi}^{0}]\\=7*15\\=105^{0}$

Hope you have understood this....

pls mark my answer as the brainliest

8 0

3 years ago

Find the measure of center: 1, 2, 3, 4, 5, 6, 7

Eva8 [605]

Answer:

Mean: 4

Median : 4

Mode: 1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

Measure of center is:

Mean: Average

Median: Middle number

Mode: Often number

Mean: Add all number then divide by the total number in data set.

1 + 2 + 3 + 4 + 5 + 6 + 7 = 28

28/7 = 4

Median: Middle number

1,2,3,4,5,6,7

Mode: most often number

1,2,3,4,5,6,7

Kavinsky

8 0

2 years ago

Read 2 more answers

Based on these results, if 250 children are asked about their favorite activity, how many children will prefer organize sports?

ser-zykov [4K]

Answer:

60 out of 250 children will prefer organized sports.

Step-by-step explanation:

We are given the results of a random survey of children between the ages of 13 and 18 about their favorite activity.

Based on these results, we are to find the number of children who will prefer organized sports if 250 children were asked about their favorite activity.

Children who will prefer organized sports = $\frac{37}{155} \times 250$ = 60

5 0

3 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

3 years ago