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3 years ago

12

Please answer. Thank you.

1 answer:

Aloiza [94]3 years ago

8 0

Answer:

G.

Step-by-step explanation:

Graph shows constant change between the weight and the cost.

3/2.25 is 1.33333333

4/3 is 1.3333333

5/3.75 is 1.3333333 as well.

Others are not constant.

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6⁄10 _______ 9⁄12 A. > B. ≤ C. = D.

Ivanshal [37]

6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)

7 0

3 years ago

Read 2 more answers

In a rectangle MPKN, the diagonals intersect each other at point O. A line segment OA is an altitude of a triangle MOP, and m∠AO

WINSTONCH [101]

Answer:

72

Step-by-step explanation:

6 0

3 years ago

Use f(x) = 1/2 x and f -1(x) = 2x to solve the problems. f(2) = 1 f−1(1) = 2 f−1(f(2)) = 2 f−1(−2) = f(−4) = f(f−1(−2)) =

vampirchik [111]

Answer:

In this problem, we are given the following functions:

$f(x)=\frac{1}{2}x$

and its inverse function:

$f^{-1}(x)=2x$

First of all, we want to calculate $f(2)$ . This can be obtained by substituting

x = 2

into f(x). Doing so, we find:

$f(2)=\frac{1}{2}\cdot 2 = 1$

Then we want to calculate $f^{-1}(1)$ . We can do it by substituting

x = 1

into $f^{-1}(x)$ . Doing so,

$f^{-1}(1)=2\cdot 1 = 2$

Then we want to calculate $f^{-1}(f(2))$ , which can be found by calculating f(2) and then using it as input for $f^{-1}(x).$ We know that

f(2) = 1

Therefore,

$f^{-1}(f(2))=f^{-1}(1)=2$

Then we want to calculate $f^{-1}(-2)$ , which can be calculated by plugging

x = -2

into $f^{-1}(x)$ . Doing so,

$f^{-1}(-2)=2\cdot (-2)=-4$

Then we want to calculate $f(-4)$ ; by substituting

x = 4

into f(x), we find

$f(-4)=\frac{1}{2}\cdot (-4)=-2$

Finally, we want to find $f(f^{-1}(-2))$

We know already that

$f^{-1}(-2)=-4$

So we have:

$f(f^{-1}(-2))=f(-4)=-2$

7 0

3 years ago

Read 2 more answers

What is an equation of the line that passes through the points (0, -4) and (-4, 6)?

olganol [36]

Answer:

The equation of the line is.

$y=-\frac{5}{2}x-4$

Step-by-step explanation:

Given:

The given points are (0, -4) and (-4, 6)

The equation of the line passing through the points $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is.

$\frac{x-x_{1}}{x_{2}-x_{1}}=\frac{y-y_{1}}{y_{2}-y_{1}}$

Thus, the equation of the line that passes through the points (0, -4) and (-4, 6) is

$\frac{x-0}{(-4)-0}=\frac{y-(-4)}{6-(-4)}$

$\frac{x}{-4}=\frac{y+4}{6+4}$

$-\frac{x}{4}=\frac{y+4}{10}$

$-\frac{10x}{4}=y+4$

$-10x=4(y+4)$

$-10x=4y+16$

$4y=-10x-16$

The above equation is divided by 2 both sides.

$2y=-5x-8$

$y=-\frac{5}{2}x-4$

Therefore, the equation of the line that passes through the points (0, -4) and (-4, 6) is $y=-\frac{5}{2}x-4$

8 0

3 years ago

Help picture below problem 16

kirill115 [55]

Answer:

Regular Hexagon

Step-by-step explanation:

There are six sides and all sides are equal

8 0

2 years ago