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Oksana_A [137]
3 years ago
8

1. The temperature was very cold. Then the temperature doubled. Then the temperature dropped by 10 degrees. Then the temperature

increased by 40 degrees. The temperature is now 16 degrees. What was the starting temperature? ​
Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

10,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

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A cheetah can travel three hours at top speed for 225 miles how many miles per hour?
jolli1 [7]

Answer:

The answer is 75 miles per hour

Step-by-step explanation:

225÷3=75 ( how many times 3 go into 225)

We can check to see if this answer is correct by multiplying 75 by 3 ( multiply 75 three times)

75×3=225

There for 75 is the correct answer

(I hope this helped you answer your question. If you want to check if I'm correct you can use a calculator! Have a wonderful day!)

:)

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3 years ago
toby used 4 inches of tape to wrap a gift how much tape will he need to wrap 5 more of the same gift?
Pani-rosa [81]

Answer:

20

Step-by-step explanation:

4*5 = 20%

4 0
3 years ago
Evaluate teh expression. 4 + 3 × [6 ÷ (4 + 2)]2 <br> A) 7 <br> B) 8 <br> C) 9 <br> D) 12
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3 years ago
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Convert the following fractions to decimals<br>9/16<br><br>6 3/5<br><br>1/4​
ZanzabumX [31]
0.5625
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3 years ago
Seorang pemilik toko sepatu ingin mengisi tokonya dengan sepatu laki-laki paling sedikit 100 pasang dan sepatu wanita paling sed
taurus [48]

Answer:

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

Step-by-step explanation:

We need to form a LPP( Linear Programming Problem) for the following problem and solve it to get the maximize the profit.

Let x denote the number of men's shoe and y denote the number of female shoes.

Maximize z= 10000x+5000y----------(1)

             x≥100 ( since a shoe store owner wants to fill his shop with at least    100 pairs of men's shoes )

            y≥150  (at least 150 pairs of women's shoes).

also x+y≤400   (The store can only accommodate 400 pairs of shoes).

         x≤150    (male shoes should not exceed 150 pairs).

⇒         100≤x≤150

Hence the optimal solution of an LPP always lie on the end points.

We have end points as:

(100,300), (150,250), (100,150),(150,150).

by putting these value in equation (1) we see which give the maximum solution.

for (100,300) i.e. x=100 and y=300:   z=2,500,000

for (150,250) i.e. x=150 and y=250:  z=2,750,000

for (100,150) i.e. x=100 and y=150: z=1,750,000

for (150,150) i.e. x=150 and y=150: z=2,250,000

Hence maximum profit is obtained at x=100 and y=300.

i.e. to maximize the profit:

<em>Number of men's shoes to be kept in store=100</em>

<em>and number of women's shoes to be kept in store=300</em>

<em>The biggest profit that can be obtained by the shop owner= </em>IDR 2,750,000.

5 0
4 years ago
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