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geniusboy [140]
2 years ago
11

Why does the chlorine atom have a partial negative charge in a molecule of hydrogen chloride?

Physics
1 answer:
bulgar [2K]2 years ago
8 0

Answer:The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen. The unequal sharing of the bonding pair results in a partial negative charge on the chlorine atom and a partial positive charge on the hydrogen atom.

Explanation:

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Consider the accuracy of recording muscle electrical activity using electrodes placed on the skin surface, compared to directly
OverLord2011 [107]

Answer: The common difference between surface EMG and intramuscular EMG is that that former is non-invasive while the later is an invasive method

Explanation:

Electromyography (EMG) is used clinically for the examination of muscle excitations (muscle electrical activity) in both normal or abnormal conditions. There are two forms of EMG includes:

--> Surface EMT and

--> Intramuscular EMT

Surface EMT is a non invasive method of examination of muscle excitations for superficial and easily accessible muscles.

Intramuscular EMT is the invasive method of examination of muscle excitations usually for deep muscles.

The difference between the two forms of EMT includes:

- surface EMT is non- invasive while intramuscular EMT is invasive

- surface EMT is used to access superficial muscle while intramuscular EMT is used to access deep muscles.

- surface EMT requires less skill and time to carry out while intramuscular EMT requires special skills and takes more time while carrying out the procedure.

8 0
3 years ago
Calculate the angular velocity of the neptune (orbital period of 165 earth period) in its orbit around the sun.
ludmilkaskok [199]
The correct answer is: Angular velocity =  1.208 * 10^{-9} rad/s

Explanation:
The angular velocity is given as:
ω = \frac{2\pi}{T} --- (1)

Where T = 165 * (365 days) * (24 hours/day) * (60 minutes/hour) * (60 seconds/minute) = 5203440000 s

Plug in the value in (1):
ω = \frac{2\pi}{5203440000} = 1.208 * 10^{-9} rad/s
7 0
3 years ago
A television has a mass of 19 kg. What is the weight of the television?
soldi70 [24.7K]
That depends on how far it is from the nearest planet. If it's on the surface of Earth, it weighs (19 kg) x (9.8 m/s^2) = 186.2 newtons.
7 0
3 years ago
Read 2 more answers
What is the frequency of a sound wave with a wavelength of 0.04 meter in air? What type of wave is
Viktor [21]
8500 Hz and Longitudinal


Speed = frequency x wavelength

Speed of sound at 20 degrees Celsius is approximately 340 m/s
4 0
2 years ago
Read 2 more answers
Assume that the physics instructor would like to have normal visual acuity from 21 cm out to infinity and that his bifocals rest
shutvik [7]

This is note the complete question, the complete question is:

One of the lousy things about getting old (prepare yourself!) is that you can be both near-sighted and farsighted at once. Some original defect in the lens of your eye may cause you to only be able to focus on some objects a limited distance away (near-sighted). At the same time, as you age, the lens of your eye becomes more rigid and less able to change its shape. This will stop you from being able to focus on objects that are too close to your eye (far-sighted). Correcting both of these problems at once can be done by using bi-focals, or by placing two lenses in the same set of frames. An old physicist instructor can only focus on objects that lie at distance between 0.47 meters and 5.4 meters.

Assume that the physics instructor would like to have normal visual acuity from 21 cm out to infinity and that his bifocals rest 2.0 cm from his eye. What is the refractive power of the portion of the lense that will correct the instructors nearsightedness?

Answer:  3.04 D

Explanation:

when an object is held 21 cm away from the instructor's eyes, the spectacle lens must produce 0.47m ( the near point) away.

An image of 0.47m from the eye will be ( 47 - 2 )

i.e 45 cm from the spectacle lens since the spectacle lens is 2cm away from the eye.

Also, the image distance will become negative

gap between lense and eye = 2cm

Therefore;

image distance d₁ = - 45cm = - 0.45m

object distance  d₀ = 21 - 2 = 19cm = 0.19m

P = 1/f = 1/ d = 1/d₀ + 1/d₁ = 1/0.19 + (-1/0.45)

P = 1/f =  5.26315789 - 2.22222222

P = 1/f = 3.04093567 ≈ 3.04 D

5 0
3 years ago
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