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11Alexandr11 [23.1K]
3 years ago
13

. Una solución acuosa de cloruro de sodio (NaCl) al 5% m/m es aquella que contiene 5 g de sal por cada 100 g de solución, esto q

uiere decir que hay a. 5 g de sal por cada 100 g de agua. b. 5 g de sal por cada 95 g de agua. c. 5 g de sal por cada 100 ml de agua. d. 5 g de sal por cada litro de agua.
Chemistry
2 answers:
Yuliya22 [10]3 years ago
8 0

Answer:

hi

Explanation:

ss7ja [257]3 years ago
4 0

Answer:

A

Explanation:

it's a

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2. How many atoms are in 5.6 moles of Na? Answer:___3.2 E 24 atoms of Na​
jeyben [28]

Answer:

5.6\frac{6.02*10^{23} }{1} = 3.4 X 10^{24}

Explanation:

the correct answer to it is 3.4 instead of 3.2. I got 3.4 from rounding it from 3.37.

8 0
3 years ago
80 points!!
ikadub [295]
Materials: laser pointer/ flashlight with a paper with a small slit, glass prism

step 1.) turn on the laser pointer point it up to the ceiling.

step 2.) point to prism, explain how the light refracts in the prism. and how it changes.

(I hope this helps!)
6 0
3 years ago
Read 2 more answers
You add 28 grams of carbon. You find the actual yield to be 181.2 grams of CO2. What is the percent yield of CO2?
liraira [26]

Answer:

79.14%

Explanation:

Given the equation : 2Fe2O3 + 3C 4Fe + 3C02

The theoretical yield of CO2 ; is 102.6g

Actual yield = 81.2 gram

Percentage yield = (actual yield / theoretical yield) * 100%

Percentage yield = (81.2 / 102.6) * 100%

Percentage yield = 0.7914230 * 100%

Percentage yield = 79.14%

Hence, tbe percentage yield of CO2 is 79.14%

4 0
3 years ago
A quantity of CO gas occupies a volume of 0.32 L at 0.90 atm and 323 K . The pressure of the gas is lowered and its temperature
Contact [7]
Mathematical formula of Ideal Gas Law is PV=nRT
  where: P-pressure, 
              V-volume
              n-number of moles; m/MW
              T-Temperature
              m-mass
              d-density ; m/V
              MW-Molecular Weight
              R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
    
Substituting the definitions to the original Gas equation becomes:
     d= P x MW / (RxT)

Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K  x 323 K
           
                d = 25.2 g / 26000 mL

                d = .0.00096 g/mL is the density of CO under the new conditions
           
5 0
4 years ago
H2O(g) → H2 + O2(g) Predict whether the reaction above would have an increase or a decrease in entropy.
nadya68 [22]
Since the reaction has one mole of reactants versus two moles of products, the reaction would have a decrease in entropy. One mole of gas exerts less pressure than two moles of gas, and therefore one mole of gas has more entropy than two moles of gas.

Hope this helps
5 0
4 years ago
Read 2 more answers
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