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nikitadnepr [17]
4 years ago
9

Write the equation for the oxidation reaction that occurred on the copper spiral when it was heated

Chemistry
1 answer:
Butoxors [25]4 years ago
8 0
Cu + O2 -----> 2CuO
( Cu^{0} -2  e^{-}  -----\ \textgreater \  Cu^{+2})    *2 / oxidation

 O_{2} +4 e^{-} ------\ \textgreater \  2O^{-2}   / reduction

------------------------------------------------------

 2Cu^{0} +   O_{2} ^{0} -----\ \textgreater \  2 Cu^{+2} + 2 O^{-2}
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