4 years ago

Write the equation for the oxidation reaction that occurred on the copper spiral when it was heated

1 answer:

8 0

Cu + O2 -----> 2CuO
$( Cu^{0} -2 e^{-} -----\ \textgreater \ Cu^{+2}) *2 / oxidation

 O_{2} +4 e^{-} ------\ \textgreater \ 2O^{-2} / reduction

------------------------------------------------------

 2Cu^{0} + O_{2} ^{0} -----\ \textgreater \ 2 Cu^{+2} + 2 O^{-2}$

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