Archimedes' principle allows us to find that the reasons why the thrust is not written when a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Archimedes' principle establishes that the thrust is equal to the weight of the dislodged liquid (fluid)
B = ρ g V
Where B is the thrust, ρ and V the density and volume of the fluid, respectively, g the acceleration due to gravity.
In the attachment you have a diagram of a system in equilibrium in air and water, we can see that in the two cases for a system in equilibrium
B -W = 0
B = W
Let's find the value of the thrust in each case and compare
Used the density
Suppose that the volume of the two bodies is the same
r
We can see that the thrust in air or other gas is about 800 times less than the thrust in liquids. This is the reason that in many problems the thrust is not written when the body is in the air.
In conclusion, using Archimedes' principle, we find that the reason why the healed thrust is not written for a body is in the air is:
- The thrust of air is about 800 times less than the thrust of a fluid
- In general the other forces (weight, tension) are much greater than thrust
Learn more about Archimedes' principle here:
brainly.com/question/787619
Hi,
mL are smaller than liters. So milk should be liters, right? Yeah it should. If yiu put milk on a scale, it would go down bc it is so heavy. If it was not as heavy, it would be a different story here. Think of it that way.
Answer:
4. 1.18 mol·L⁻¹
14. See below.
Explanation:
4. Dilution calculation
V₁c₁ = V₂c₂
Data:
V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹
V₂ = 950 mL; c₂ = ?
Calculation:
c₂ = c₁ × V₁/V₂
c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹
The new concentration is 1.18 mol·L⁻¹
.
14. Boyle's Law graphs
We can write Boyle's Law as
pV = k or p = k/V or V= k/p
p and V are inversely related.
(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.
(b) p = k/V =k(1/V)
1/V = (1/k)p
y = m x + 0
A graph of 1/V vs p is a straight line.
Applying the conservation of mass:
Mass during bombardment:
242 (curium atom) + 4 (alpha particle)
= 246
This must equal the mass after bombardment:
1 (neutron) + x (unknown product)
246 = 1 + x
x = 245
The product is Californium-245
Answer:
kilopascal, torr, and atmosphere
Explanation: