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Hoochie [10]
3 years ago
13

To complete your degree and then go through graduate school, you will need $95,000 at end of each of the next 8 years. Your Aunt

offered to put you through school, and she will deposit in a bank paying 4.00% interest a sum of money that is sufficient to provide you with the needed 8 withdrawals of $95,000 each.
Required:
a. How large of a deposit must she make today?
b. How much will be in the account immediately after you make the 3rd $95,000 withdrawal?
c. How much will be in the account immediately after you make all the withdrawals including the last one in 8 years?
d. Now, if you decide to drop out of school today and not make any of the withdrawal, but instead keep your auntâs money, that she deposited today, in the account that is earning 4.00%, how much would you have at the end of 8 years?
Business
1 answer:
VARVARA [1.3K]3 years ago
5 0

Answer:

PMT = $95,000

Rate = 4%

Life = 8 years

a. Amount to be deposited today

= PV(Rate, N, -PMT)

= PV(4%, 8, -95,000)

= $639,610.76

b. Amount in account after 3rd withdrawal

= PV(Rate, N, -PMT)

= PV(4%, 5, -95,000)

= $422,913.12

c. Balance in account after 8th withdrawal

= = PV(Rate, N, -PMT)

= PV(4%, 0, -95,000)

= $0

d. How much would you have at the end of 8 years?

= FV(4%, 8, -639610.76)

= $875,351.49

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Answer:

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8 0
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Twenty years ago, a family purchased a vacant lot for $26,500. they made no improvements during the time they owned the property
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To find the gross profit margin found by:
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3 0
3 years ago
Read 2 more answers
A high-interest savings account pays 5. 5% interest compounded annually. If $300 is deposited initially and again at the first o
Arte-miy333 [17]

For the given question, the summation that represents the money in account is:

\begin{aligned}\sum_{10}^{n=1}316.5(1.055)^{n-1} \end{aligned}

The principal amount if compounded annually, the formula that represents the amount to be received after n years is:

\rm A = P(1 + \dfrac{r}{100})^t where A is the amount received after compounding, P is the principal, r is the rate of interest and t is the tenure.

<h3>Solution:</h3>

Given:

Annual interest rate(r) is 5.5%

Principal is(P) $300

Tenure is(t) 10 years

On substituting the values in the formula \rm A = P(1 + \dfrac{r}{100})^t

The amount received after compounding at the end of 1 year will be:

\rm A = 300(1 + \dfrac{5.5}{100})^1\\&#10;\\&#10;A=300(1.055)\\&#10;\\&#10;A=\$316.5

Similarly, the amount to be received after 2 years will be:

316.5+316.5(1.055)

The amount received after 10 years will be:

316.5+316.5(1.055)+316.5(1.055)^2+.......  upto 10 years

Therefore the summation that represents the money in account after 10 years is:

\begin{aligned}\sum_{10}^{n=1}316.5(1.055)^{n-1} \end{aligned}

Learn more about compound interest here:

brainly.com/question/25857212

5 0
2 years ago
Way Cool produces two different models of air conditioners. The company produces the mechanical systems in their components depa
katrin [286]

Answer:

Plantwide Overhead Rate $ 213.61 per hour

1) Overhead Cost Model 145=$ 487062.56

1) Overhead Cost Model 211= $ 1153494

<u>Total Cost per unit      </u> Model 145  <u>           696.29       </u>  Model 212 <u>                        $406.56</u>

Explanation:

Plantwide Overhead Rate = Total Estimated Overhead/ No of Machine Hours

        Process Activity Overhead                Cost Driver Quantity

Components Changeover $ 459,500        Number of batches 810

$ 459,500/810= $567.28 per batch

Machining 301,600                                       Machine hours 7,680

301,600/ 7,680 = $ 39.27

Setups 227,500                                              Number of setups 80

<u>227,500   /80=2843.75 per set up                                                    </u>

<u>$ 459,500 +301,600  +227,500  =</u><u>$ 988,600                                    </u>

Finishing Welding $ 180,500                         Welding hours 4,900

$ 180,500/  4,900= $ 36.84 per welding hour

Inspecting 222,000                                    Number of inspections 815

222,000/815 = $ 272.39 per number of inspections

Rework 60,700                                            Rework orders 230

<u> 60,700 /230 = 263.91 per rework order                                                 </u>

<u>$ 180,500+ 222,000+  60,700 =</u><u>$ 463,200                                           </u>

Support Purchasing $ 135,500                  Purchase orders 525

$ 135,500 / 525 = $ 258.10 per purchase order

Providing space 31,550                              Number of units 4,800

31,550/4800=   $ 6.57 per number of unit

Providing utilities 60,110                             Number of units 4,800

<u>60,110  / 4800= $ 12.53                                                                             </u>

<u>$ 135,500+ 31,550+60,110  </u><u>=$ 227,160                                                     </u>

Additional production information concerning its two product lines follows.

                                       Model 145           Model 212

Units produced                 1,600                   3,200

Welding hours                  2,000                   2,900

Batches                                405                     405

Number of inspections         485                     330

Machine hours                   2,280                   5,400

Setups                                 40                          40

Rework orders                       130                      100

Purchase orders                   350                        175

1)Plantwide Overhead Rate = Total Estimated Overhead/ No of Machine Hours

Adding the Estimated Sub Totals we get

Total Estimated Overhead=$ 988,600  + $ 463,200  + $ 227,160

Total Estimated Overhead= $ 1678960

No of Machine Hours= 7860 (given)

Plantwide Overhead Rate =$ 1678960/7860= 213.608= $ 213.61 per hour

Overhead Cost Model 145=$ 213.61 per hour* 2,280  hours

1) Overhead Cost Model 145=$ 487062.56

1) Overhead Cost Model 211=$ 213.61 per hour* 5400 hours= $ 1153494

2)                          Model 145                               Model 212.

Direct Materials                                                     $ 130

Direct Labor             $200

Overhead Costs       $567.28* 405                        $567.28*405

                                     =   229784.4                            =    229784.4

                                  $ 39.27*2280                      $ 39.27*5400

                                      = 89535.6                             =212058

                                    2843.75*40                        2843.75* 40

                                      =113750                              =113750

Subtotal                       433070                                 555592.4

                                  $ 36.84*2000                        $ 36.84 *2900

                                  =73680 i                                     = 106836

                                  $ 272.39* 485                         $ 272.39* 330

                                     =132109.5 ii                              =  89888.7

                                    263.91*130                            263.91 *100

                                      =34308.3 iii                             =26391

Subtotal                 i+ii+iii= 240097.8                               223115.7

                                    $ 258.10*350                     $ 258.10*175

                                       =90335 i                                = 45167.5  a

                                      $ 6.57 *1600                     $ 6.57 *3200

                                       = 10512 ii                                 =21024  b

                                      $ 12.53 *1600                       $ 12.53 *3200

                                        =20048 iii                              40096  c

Subtotal                 i+ii+iii= 120895                               a+b+c = 106287.5

Total Overhead             794062.8                                      884995.6    

No of Units                   1600                                                3200        

Total Overhead Cost Per Unit   496.29                           276.56

Direct Labor                        $200                            

Direct Materials              <u>                                             $130</u>

<u>Total Cost per unit                 696.29                               $406.56</u>

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Explanation:

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