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Schach [20]
3 years ago
14

If a 0.75 efficient motor produces 150 W of useful power, what was the input power? *

Physics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

<em>The input power is 200 W</em>

Explanation:

<u>Motor Efficiency</u>

The efficiency of a motor can be calculated as follows:

\displaystyle \beta=\frac{P_o}{P_i}

Where:

β   = efficiency

Po = Output power

Pi  = Input power

Solving for Pi:

\displaystyle P_i=\frac{P_o}{\beta}

The efficiency is β=0.75 and the output power is Po=150 W, thus the input power is:

\displaystyle P_i=\frac{150}{0.75}

P_i=200 \ W

The input power is 200 W

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Answer:

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Explanation:

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Therefore,

F = \frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(235\ kg)(1.37\ x\ 10^{12}\ kg)}{(2.59\ x\ 10^{4}\ m)^{2}}

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Answer:

0.36

Explanation:

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What we have so far:
*Distance you walked the dog = 0.75 miles
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Step 2) 0.75 x 1.61/1 (km)<--- notice that we deleted the unit "miles". We did that to make sure that the result will be in kilometers (km).

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