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3 years ago

An artesian system is present when groundwater __________.

Physics

1 answer:

ahrayia [7]3 years ago

4 0

<h2>Answer: under pressure rises above the aquifer level</h2>

Explanation:

An artesian system is one that connects with an accumulation of water (aquifer) whose surface or level is above the surface of the system or well.

In other words, the upper limit of the aquifer is higher than the opening through which the liquid flows in the artesian well. This has the advantage that the water spreads without needing to be pumped.

It should be noted that its name comes from the region of <u>Artois</u>, France, where in 1126 the oldest well in Europe was drilled with these characteristics.

Therefore:

<h2>An artesian system is present when groundwater <u>under pressure rises above the aquifer level.</u></h2>

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Svetllana [295]

Answer:

$P_G = 14.03 \ psig$

$h_m = 0.148 \ m$

Explanation:

From the question we are told that

The pressure of the manometer when there is no gas flow is $P_{m} = 15.5 \ psig = 15.5 * 6894.76 = 106868.78 \ N/m^2$

The level of mercury is $h = 950 \ mm = 0.950 \ m$

The drop in the mercury level at the visible arm is $d = 39.0 = 0.039 \ m$

Generally when there is no gas flow the pressure of the manometer is equal to the gauge pressure which is mathematically represented as

$P_g = P_m = g * \delta h * \rho$

Here $\rho$ is the density of mercury with value $\rho = 13.6 *10^{3} kg/m^3$

and $\delta h$ is the difference in the level of gas in arm one and two

$\delta h = \frac{106868.78}{ 13.6 *10^{3} * 9.8 }$

$\delta h = 0.802 \ m$

Generally the height of the mercury at the arm connected to the pipe is mathematically represented as

$h_m = 0.950 - 0.802$

=> $h_m = 0.148 \ m$

Generally from manometry principle we have that

$P_G + \rho * g * d - \rho * g * [h - (h_m + d)] = 0$

Here $P_G$ is the pressure of the gas

$P_G +13.6 *10^{3} * 9.8 * 0.039 - 13.6 *10^{3} * 9.8 * [0.950 - (0.148 + 0.039)] = 0$

$P_G = 9.6724 04 *10^{4} \ N/m^2$

converting to psig

$P_G = \frac{ 9.6724 04 *10^{4} }{6894.76}$

$P_G = 14.03 \ psig$

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3 years ago

An automobile steering wheel is shown. What is the ideal mechanical advantage? If the AMA is 8, what is the efficiency of the st

Mars2501 [29]

1. Ideal Mechanical Advantage (IMA): 9

Explanation:

For a wheel and axle system like the steering wheel, the IMA is given by:

$IMA=\frac{r_w}{r_a}$

where

$r_w$ is the radius of the wheel

$r_a$ is the radius of the axle

For the steering wheel of the problem, we see that $r_w = 18 cm$ and $r_a=2 cm$ , so the IMA is

$IMA=\frac{18 cm}{2 cm}=9$

2. Efficiency: 88.9%

Explanation:

The efficiency of a system is defined as the ratio between the AMA (actual mechanical advantage) and the IMA:

$\eta=\frac{AMA}{IMA}\cdot 100$

In this problem, AMA=8 and IMA=9, so the efficiency is

$\eta=\frac{8}{9}\cdot 100=88.9\%$

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4 years ago

An object of mass m is dropped from height h above a planet of mass M and radius R. Find an expression for the objectâ€™s speed

Oksana_A [137]

Answer:

Explanation:

Given

mass of object is m

Mass of planet is M

radius of planet is R

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$E_1=-\frac{GMm}{R+h}$

When it falls on earth with some velocity v

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$=\frac{1}{2}mv^2+\frac{-GMm}{R}$

As Energy is conserved therefore

$=E_2$

$\frac{-GMm}{R+h}=\frac{1}{2}mv^2+\frac{-GMm}{R}$

$\frac{1}{2}mv^2=\frac{GMmh}{R(R+h)}$

$v=\sqrt{\frac{2GMh}{R(R+h)}}$

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3 years ago

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musickatia [10]

Answer:

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Explanation:

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