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bekas [8.4K]
3 years ago
7

What type of energy are the water molecules gaining during a phase change​

Physics
1 answer:
kondor19780726 [428]3 years ago
8 0

Answer:

<h2><em>Potential energy.</em></h2>

Explanation for yall who dont get:

Basically, the energy that is changing during a phase change is potential energy. Why? Cuz, during a phase change, the heat added (Potential Energy INCREASES) or released (Potential Energy DECREASES) allow the molecules to move apart or be together.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<em>Leme know if im wrong.  </em>

<em>GL.</em>

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Write the equation for eccentricity
Svetradugi [14.3K]
<span>e=ca{\displaystyle e={\frac {c}{a}}}.</span>

3 0
4 years ago
There is an old physics joke involving cows, and you will need to use its punchline to solve this problem
aleksandr82 [10.1K]

Answer:

The angle of deflection will be "1.07 × 10⁻⁷°".

Explanation:

The given values are:

Mass of a cow,

m = 1100 kg

Mass of bob,

mb = 1 kg

The total distance between a cow and bob will be,

d = 2 m

Let,

The tension be "t".

The angle with the verticles be "\theta".

Now,

Vertically equating forces

⇒  T\times Cos \theta =mb\times g ...(equation 1)

Horizontally equating forces

⇒  T\times Sin \theta = G\times M\times \frac{mb}{d^2} ...(equation 2)

From equation 1 and equation 2, we get

⇒  tan \thata=\frac{G\times M}{g\times d^2}

O putting the estimated values, will be

⇒  \theta = tan(\frac{6.674\times 10^{-11}\times 1100}{9.8\times 2^2} )

⇒  \theta = 1.07\times 10^{-7}^{\circ}

6 0
4 years ago
An arrow is shot parallel to horizontal from a height of 1.4 meters. It has a velocity of 49 m/s.
Mkey [24]

The time taken for the arrow to hit the ground is 0.53 s.

The horizontal distance traveled by the arrow is 25.97 m.

The given parameters:

  • Initial horizontal velocity, v_x = 49 m/s
  • Initial vertical velocity, v_y = 0

<h3>What is time of motion?</h3>
  • This is the time taken for a projectile to land on the plane of projection.

The time of motion is calculated as follows;

h = v_yt + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1.4}{9.8} }\\\\t = 0.53 \ s

The horizontal distance traveled by the arrow is calculated as follows;

X = v_x t\\\\X = (49\ m/s) \times (0.53 \ s)\\\\X = 25.97 \ m

Learn more about time of motion here: brainly.com/question/2364404

5 0
2 years ago
Please help!
andrew-mc [135]

Answer:

V=W/Q

107V= W/17C

= We= 107×17 J

= 1819 J

Explanation:

hope it helps

3 0
3 years ago
The capacity to do work is called? A. temperature C. force
lesya692 [45]
Force is a capacity to do work
7 0
3 years ago
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