At a temperature of 298 K, the Henry's law constant is 0.00130 M/atm for oxygen. The solubility of oxygen in water 1.00 atm would be calculated as follows:
<span>S = (H) (Pgas) = 0.00130 M / atm x 0.21 atm = 0.000273 M
</span>
At 0.890 atm,
<span>S = (H)(Pgas) = 0.00130 M / atm x 0.1869 atm = 0.00024297 M</span>
<span>
If atmospheric pressure would suddenly change from 1.00 atm to 0.890 atm at the same temperature, the amount of oxygen that will be released from 3.30 L of water in an unsealed container would be as follows</span>
<span>
3.30 L x (0.000273 mol / L) = 0.0012012 mol</span>
3.30 L x (0.00024297 mol / L) = 0.001069068 mol
0.0012012 mol - 0.001069068 mol = 0.000132 mol
The following statements apply:
1. Resolution of low boiling solutes is maintained.
2. Retention times of high boiling solutes are decreased.
Temperature programming refers to the process of increasing the temperature of gas chromatography column as a function of time. Temperature programming is usually applied to samples which contain a mixture of components whose boiling points are within narrow ranges
Answer:
acceleration m/s²
Explanation:
The units on the left side of the equation are units of length. The units on the right side of the equation must be units of length also. Acceleration times time squared gives length.
Answer:
Δx = 3.99 m
Explanation:
To determine distance, use kinetic energy
will make it short and easy.
KE=1/2mv2 and KE=Δxmgμ
Set the equations equal to each other
1/2mv2=Δxmgμ (Note: The masses cancel
)
1/2v2=Δxgμ Solve for Δx
where g=9.8
Δx=v2/(2gμ) Δx = 25 / (2 * 9.8 * 0.32) Δx = 3.99 m
Please let me know if its correct, if not report it so we can correct it.