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Sunny_sXe [5.5K]
3 years ago
5

As you may have experienced yourself, water alone will not remove oil from a dirty dish. Why does soap work to remove oil

Physics
2 answers:
bulgar [2K]3 years ago
7 0

Answer:

The combination of the two, water and soap, form bubbles that make a compound capable of removing the oil. The soap lifts the oil and dirt and becomes suspended in the water then we rinse off the soapy water and down goes the oil with it.

Explanation:

Alexandra [31]3 years ago
5 0

Answer:

Soap breaks up the oil into smaller drops, which can mix with the water. It works because soap is made up of molecules with two very different ends (one end of molecules are hydrophilic, so they love water; the other end of molecules is hydrophobic, so they hate water).

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An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the
pochemuha

Answer:

The best option is for the following option m = 15 [g] and V = 5 [cm³]

Explanation:

We have that the density of a body is defined as the ratio of mass to volume.

Ro =m/V

where:

Ro = density = 3 [g/cm³]

Now we must determine the densities with each of the given values.

<u>For m = 7 [g] and V = 2.3 [cm³]</u>

Ro=7/2.3\\Ro=3.04 [g/cm^{3} ]

<u>For m = 10 [g] and V = 7 [cm³]</u>

<u />Ro=10/7\\Ro=1.42[g/cm^{3} ]\\<u />

<u>For m = 15 [g] and V = 5 [cm³]</u>

<u />Ro=15/5\\Ro=3[g/cm^{3} ]\\<u />

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5 0
2 years ago
A generator with �# ' = 300 V and Zg = 50 Ω is connected to a load ZL = 75 Ω through a 50-Ω lossless line of length l = 0.15λ. (
ki77a [65]

Answer:

a. Zin = 41.25 - j 16.35 Ω

b. V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

c.  Pin = 216 w

d. PL = Pin = 216 w

e. Pg = 478.4 w , Pzg = 262.4 w

Explanation:

a.

Zin = Zo * [ ZL + j Zo Tan (βl) ] / [ Zo + j ZL Tan (βl) ]  

βl = 2π / λ * 0.15 λ = 54 °

Zin = 50 * [ 75 + j 50 Tan (54) ] / [ 50 + j 75 Tan (54) ]

Zin = 41.25 - j 16.35 Ω

b.

I₁ = Vg / Zg + Zin ⇒ I₁ = 300 / 41.25 - j 16.35 = 3.24 e ¹⁰ ¹⁶

V₁ = I₁ * Zin = 3.24 e ¹⁰ ¹⁶ * ( 41.25 - j 16.35)

V₁ = 143. 6 e⁻ ¹¹ ⁴⁶

c.

Pin = ¹/₂ * Re * [V₁ * I₁]

Pin = ¹/₂ * 143.6 ⁻¹¹ ⁴⁶ * 3.24 e ⁻ ¹⁰ ¹⁶ = 143.6 * 3.24 / 2 * cos (21.62)

Pin = 216 w

d.

The power PL and Pin are the same as the line is lossless input to the line ends up in the load so

PL = Pin

PL = 216 w

e.

Pg Generator

Pg = ¹/₂ * Re * [ V₁ * I₁ ] = 486 * cos (10.16)

Pg = 478.4 w

Pzg dissipated

Pzg = ¹/₂ * I² * Zg = ¹/₂ * 3.24² * 50

Pzg = 262.4 w

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