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3 years ago

As you may have experienced yourself, water alone will not remove oil from a dirty dish. Why does soap work to remove oil

Physics

2 answers:

bulgar [2K]3 years ago

7 0

Answer:

The combination of the two, water and soap, form bubbles that make a compound capable of removing the oil. The soap lifts the oil and dirt and becomes suspended in the water then we rinse off the soapy water and down goes the oil with it.

Explanation:

Alexandra [31]3 years ago

5 0

Answer:

Soap breaks up the oil into smaller drops, which can mix with the water. It works because soap is made up of molecules with two very different ends (one end of molecules are hydrophilic, so they love water; the other end of molecules is hydrophobic, so they hate water).

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An apple falls from a tree and 2.5 seconds later hits the ground. How fast is the apple falling when it hits the ground? Neglect

denis-greek [22]

Answer:

Explanation:

<h2>Since the ball rises for 2.5 s, the time to fall is 2.5 s. The acceleration is 9.8 m/s2 everywhere, even when the velocity is zero at the top of the path. Although the velocity is zero at the top, it is changing at the rate of 9.8 m/s² downward.</h2>

6 0

2 years ago

Someone answer asapp

garik1379 [7]

Potential energy is highest at the top of the loop, and kinetic energy is highest at the bottom of the loop.

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3 years ago

Read 2 more answers

Hooke's law describes a certain light spring of unstretched length 31.8 cm. when one end is attached to the top of a doorframe a

lubasha [3.4K]

Answer:

Explanation:

extension in the spring = 40.4 - 31.8 = 8.6 cm = 8.6 x 10⁻² m .

kx = mg

k is spring constant , x is extension , m is mass

k x 8.6 x 10⁻² = 7.52 x 9.8

k = 856.93 N/m

= 857 x 10⁻³ KN /m

b ) Both side is pulled by force of 188 N .

Tension in spring = 188N

kx = T

856.93 x = 188

x = .219.38 m

= 21.938 cm

= 21.9 cm .

length of spring = 31.8 + 21.9

= 53.7 cm .

6 0

2 years ago

(b) A car of mass 3000 kg travels at a constant velocity of 5.0 m/s.

Tamiku [17]

Answer:

16.7 s

Explanation:

T= <u>Vf - Vo</u> a= <u>F</u>

a m

4,500 / 3000 = 1.5 (a)

30 - 5 / 1.5(a) = 16.7 s

4 0

3 years ago

You pull with a force of 295 N on a rope that is attached to a block of mass 22 kg, and the block slides across the floor at a c

Sergeeva-Olga [200]

Answer:

Fnet = 0

Explanation:

Since the block slides across the floor at constant speed, this means that it's not accelerated.
According Newton's 2nd Law, if the acceleration is zero, the net force on the sliding mass must be zero.
This means that there must be a friction force opposing to the horizontal component of the applied force, equal in magnitude to it:

$F_{appx} = F_{app} * cos \theta = 295 N * cos 35 = 242 N (1)$

In the vertical direction, the block is not accelerated either, so the sum of the normal force and the vertical component of the applied force, must be equal in magnitude to the force of gravity on the block:

$F_{appy} = F_{app} * cos \theta = 295 N * sin 35 = 169 N (2)$

⇒ 169 N + Fn = Fg = 216 N (3)

This means that there must be a normal force equal to the difference between Fappy and Fg, as follows:
Fn = 216 N - 169 N = 47 N (4)

6 0

2 years ago