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djverab [1.8K]
3 years ago
5

Helpppppppppp!!!!!!!!!!...​

Physics
2 answers:
OverLord2011 [107]3 years ago
8 0

Answer:

i can't see the picture pls can you send a link or no

Explanation:

jok3333 [9.3K]3 years ago
5 0

Explanation:

Hey there!

Height(h)= 1.8m

Mass(m)= 14kg

Potential energy= m.h.g

Where "m" means mass, "h" means vertical height and "g" means gravity.

Now, put all values.

P.e = 14kg * 1.8m * 10m/s^2

= 252kg.m^2/s^2

Therefore, The potential energy was 252kg.m^2/s^2.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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Using land according to its capability. protect the soil surface with some form of cover. control runoff before it develops into an erosive force
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The closeness of measured values to an accepted value is the BLANK of the data ?
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When you refer to how close a measured value is to a standard, accepted or known value, you are talking about the ACCURACY of the data. This is the definition of accuracy when it comes to engineering and other fields of science. 

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3 years ago
Twin A makes a one way trip at 0.6c to a star 12 light years away while twin B stays on Earth. Each twin sends the other a signa
hram777 [196]

Answer:

8 signals received by twin A during the trip.

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Given that,

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Time = 1 year

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T=t\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}

Put the value into the formula

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Similarly,

The expression for distance cover by A

D=d\sqrt{1-\dfrac{v^2}{c^2}}

D=12\sqrt{1-(0.6)^2}

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t=\dfrac{D}{v}

t=\dfrac{9.6}{0.6}

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n=\dfrac{t}{T}

Put the value into the formula

n=\dfrac{16}{2}

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7 0
3 years ago
Why is accelration negative when velocity is positive.​
Sindrei [870]

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8 0
2 years ago
A short current element dl⃗ = (0.500 mm)j^ carries a current of 5.40 A in the same direction as dl⃗ . Point P is located at r⃗ =
SashulF [63]

Answer:

The magnetic field along x axis is

B_{x}=1.670\times10^{-10}\ T

The magnetic field along y axis is zero.

The magnetic field along z axis is

B_{z}=3.484\times10^{-10}\ T

Explanation:

Given that,

Length of the current element dl=(0.5\times10^{-3})j

Current in y direction = 5.40 A

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|\vec{r}|=\sqrt{(0.730)^2+(0.390)^2}

|\vec{r}|=0.827\ m

We need to calculate the magnetic field

Using Biot-savart law

B=\dfrac{\mu_{0}}{4\pi}\timesI\times\dfrac{\vec{dl}\times\vec{r}}{|\vec{r}|^3}

Put the value into the formula

B=10^{-7}\times5.40\times\dfrac{(0.5\times10^{-3})\times(-0.730)i+(0.390)k}{(0.827)^3}

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Put the value into the formula of magnetic field

B=10^{-7}\times5.40\times\dfrac{(0.000175i+0.000365k)}{(0.827)^3}

B=1.670\times10^{-10}i+3.484\times10^{-10}k

Hence, The magnetic field along x axis is

B_{x}=1.670\times10^{-10}\ T

The magnetic field along y axis is zero.

The magnetic field along z axis is

B_{z}=3.484\times10^{-10}\ T

7 0
3 years ago
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